A basketball player is shooting free throws blindfolded. He shoots in groups of 4 shots. Assume that it is equally likely that he will hit or miss a shot. Design and do a simulation to determine the probability that he will hit at least 75% of his shots within the groups. (Hint: Use coins.)
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MMMM, MMMH, MMHM, MHMM, HMMM, MMHH, MHMH, HMMH, MHHM, HMHM, HHMM, MHHH, HMHH, HHMH, HHHM, HHHH
He hit at least 75% in 5 occasions.
Therefore, P(hit at least 75%) = 5/16
Answer:
Use 4 coins. Let heads = hit and tails = miss. Toss each coin and record the results in a table. Coin 1Coin 2Coin3Coin 4Set 1HHHHSet 2HTHHSet 3HHTHSet 4THTTSet 5
Repeat the coin tosses until you have recorded 50 sets of 4 tosses each. b. Count the successful outcomes—those with three or four heads. Coin 1Coin 2Coin3Coin 4SuccessSet 1HHHHxSet 2HTHHxSet 3HHTHxSet 4THTTSet 5
Step-by-step explanation:
Related Questions
Please help how do I do this?
Choose the correct simplification of the expression (3x − 6)(2x2 − 4x − 5).6x3 − 24x2 + 9x − 30 6x3 + 9x + 30 6x3 − 24x2 + 9x + 30 6x3 − 24x2 + 39x + 30
9+10=? .................................................... . .
Jim likes to day-trade on the internet. On a good day, he averages a $1100 gain. On a bad day, he averages a $900 loss. Suppose that he has good days 25% of the time, bad days 35% of he time, and the rest of the time he breaks even
For any value of x, h(x) will always be greater than g(x).
g(x) > h(x) for x = -1.
g(x) < h(x) for x = 3.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
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1st and 2nd options are out
for x=-1
g(-1)=1
h(-1)=-1
3rd is true
4th
false
for all values except zero, g(x)>h(x)
correct ones are
g(x) > h(x) for x = -1.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
Answer: g(x) > h(x) for x = -1.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
Step-by-step explanation:
Given functions: and
When x=0, and
∴ at x=0, g(x)=h(0)
Therefore the statements "For any value of x, g(x) will always be greater than h(x)." and "For any value of x, h(x) will always be greater than g(x)." are not true.
When x=-1, and
∴g(x) > h(x) for x = -1. ......................(1)
When x=3, and
∴ g(x) > h(x) for x = 3....................(2)
⇒g(x) < h(x) for x = 3. is not true.
From (1) and (2),
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
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We know that Scott has put 6 rows with 5 stickers each.
The total number of stickers available with Scott = 5*6 = 30 stickers
These 30 stickers are now placed in 5 rows with equal number of stickers in each row.
Number of stickers in each row= Total number of stickers available/number of rows
Number of stickers in each row = 30/5 = 6 stickers
Number of stickers in each row now would be = 6 stickers
Ο Α) π
B) 1.425
Oc) 50
OD) -4
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Rational numbers are numbers that aren’t already expressed as a quotient or fraction.
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Answer:
No.
Step-by-step explanation:
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Final answer:
The correct option is d.
To solve for x in similar triangles ABC and PQR, set up the proportion AB/PQ = DC/QR and solve for x.
Explanation:
To set up the proportion to solve for x in similar triangles ABC and PQR, we need to compare the corresponding sides. AB corresponds to PQ, so we can set up the proportion as follows:
AB/PQ = DC/QR
Substituting the given values, the proportion becomes:
18/12 = 24/(x-2)
Simplifying further, we can solve for x by cross multiplying and solving the resulting equation.
Learn more about Similar Triangles here:
#SPJ2
The complete question is given below:
It is given that two triangles are similar, ABC and PQR. AB= 18 units and DC= 24 units. PQ= 12 units and QR= x-2 units. Set up a proportion to solve for x in the following similar triangles.
a. 18/24 = (x-2)/12
b. 18/12 = (x-2)/24
c. 18/12 = 24/(x-2)
d. 18/12 = 24/x - 2
Answer:
C
Step-by-step explanation:
I took the quiz and it was C! Hope this helps :)