MATHEMATICS COLLEGE

What are five qualities of an entrepreneur that you can use to help you navigate the ""new normal ""

Answers

Answer 1

Answer:

Risk taking

Vision driven

Passionate

Goal oriented

Decision maker.

Step-by-step explanation:

An entrepreneur is a person who sets up a business, manages it and work towards maximizing profit.

In order to be able to navigate the "new normal", these five qualities are very essential in an entrepreneur if he/she wishes to go far.

Answer 2

Answer:

1. Integrity

2. Self discipline

3. Clear sense of direction

4 . Persistence

5. Action oriented and decisive

Step-by-step explanation:

1. Integrity can be define as the practice of being honest and showing a consistent and uncompromising adherence to strong moral and ethical principles and values.

2. Self discipline or Self-control, can be described as an aspect of inhibitory control, is the ability to regulate one's emotions, behavior and thought in the face of temptations and impulses.

3.. When have a clear sense if direction, we mean that person seem to have clear ideas about what they want to do or achieve.

4. When we say someone who is persistent, that person continues doing something or tries to do something in a determined but often unreasonable way.

5. Action oriented and decisive can be define as an action or actions done quickly and with confidence. How to use decisive action in a sentence.

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HELP ME!!!! MY HOMEWORK IS SOOO CONFUSING

Rewrite the expression without using a negative exponent.12x^−4
Simplify your answer as much as possible.

Answers

12x^-4 =
12 * x^-4 =
12 * 1/(x^4) =
12 / (x^4)

12x^-4
To make the exponent positive you have to bring the term x^-4 down so your answer would be= 12/x^4

Convert 51.7% to a fraction in simplest form and a decimal.

Answers

0.517 as a decimal 517/10 as a fraction

The function A(r)=πr^2 may be used to find the area of a circle with radius r. Find the area of a circle whose radius is 11 centimeters. Please help me ASAP!!!!!!! :(

Answers

Just evaluate the function: A(r) = πr² by substituting 11 in for 'r'

so A(11) = π(11)²

or Area = 121π

any help would be great

Answers

Answer:

k = P - m - n

Step-by-step explanation:

The question is asking you to rearrange the equation so that k is alone on one side.

P = k + m + n

P - k = (k + m + n) - k

P - k = m + n

(P - k) - P = m + n - P

-k = m + n - P

-1(-k) = -1 (m + n - P)

k = -m - n + P

The equation is completely simplified so this is your answer.

The temperature, H, in °F, of a cup of coffee t hours after it is set out to cool is given by the following equation. H = 70 + 120(1/4)t (a) What is the coffee's temperature initially (that is, at time t = 0)? 190 °F What is the coffee's temperature after 1 hour? 100 °F What is the coffee's temperature after 2 hours? (Round your answer to one decimal place.) 2 °F (b) How long does it take the coffee to cool down to 85°F? (Round your answer to three decimal places.) 5 hr How long does it take the coffee to cool down to 75°F? (Round your answer to three decimal places.) 5 hr

Answers

Answer:

The temperature a t = 0 is 190 °F

The temperature a t = 1 is 100 °F

The temperature a t = 2 is 77.5 °F

It takes 1.5 hours to take the coffee to cool down to 85°F

It takes 2.293 hours to take the coffee to cool down to 75°F

Step-by-step explanation:

We know that the temperature in °F, of a cup of coffee t hours after it is set out to cool is given by the following equation:

$H(t)=70+120((1)/(4))^t$

a) To find the temperature a t = 0 you need to replace the time in the equation:

$H(0)=70+120((1)/(4))^0\nH(0)=70+120\cdot 1\nH(0) = 70+120\nH(0)=190 \:\°F$

b) To find the temperature after 1 hour you need to:

$H(1)=70+120((1)/(4))^1\nH(1)=70+120((1)/(4))\nH(1) = 70+30\nH(1)=100 \:\°F$

c) To find the temperature after 2 hours you need to:

$H(2)=70+120((1)/(4))^2\nH(2)=70+120((1)/(16))\nH(2) = 70+(15)/(2) \nH(2)=77.5 \:\°F$

d) To find the time to take the coffee to cool down $85 \:\°F$ , you need to:

$85 = 70+120((1)/(4))^t\n70+120\left((1)/(4)\right)^t=85\n70+120\left((1)/(4)\right)^t-70=85-70\n120\left((1)/(4)\right)^t=15\n(120\left((1)/(4)\right)^t)/(120)=(15)/(120)\n\left((1)/(4)\right)^t=(1)/(8)$

$\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right)$

$\ln \left(\left((1)/(4)\right)^t\right)=\ln \left((1)/(8)\right)$

$\mathrm{Apply\:log\:rule}=\log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$t\ln \left((1)/(4)\right)=\ln \left((1)/(8)\right)$

$t=(\ln \left((1)/(8)\right))/(\ln \left((1)/(4)\right))\nt=(3)/(2) = 1.5 \:hours$

e) To find the time to take the coffee to cool down $75 \:\°F$ , you need to:

$75=70+120\left((1)/(4)\right)^t\n70+120\left((1)/(4)\right)^t=75\n70+120\left((1)/(4)\right)^t-70=75-70\n120\left((1)/(4)\right)^t=5\n\left((1)/(4)\right)^t=(1)/(24)$

$\ln \left(\left((1)/(4)\right)^t\right)=\ln \left((1)/(24)\right)\nt\ln \left((1)/(4)\right)=\ln \left((1)/(24)\right)\nt=(\ln \left(24\right))/(2\ln \left(2\right)) \approx = 2.293 \:hours$

An experiment is pulling a ball from an urn that contains 3 blue balls and 5 red balls. a.) Find the probability of getting a red ball. b.) Find the probability of getting a blue ball. c.) Find the odds for getting a red ball. d.) Find the odds for getting a blue ball.