Lita jogged 2 2/3 miles more on Wednesday than she did on Tuesday. She jogged 4 1/2 miles on Wednesday. Write and solve an equation to find how many miles she jogged on tuesday

Answers

Answer 1
Answer:

Answer:

T = W - 8/3 .....1

T = 11/6 miles

T = 1 5/6 miles

Step-by-step explanation:

Let T and W represent the number of miles Lita jogged on Tuesday and Wednesday respectively.

From the question;

Lita jogged 2 2/3 miles more on Wednesday than she did on Tuesday

W = T + 2 2/3

T = W - 2 2/3

T = W - 8/3 .....1

She jogged 4 1/2 miles on Wednesday;

W = 4 1/2

W = 9/2

Substituting the value of W into equation 1;

T = 9/2 - 8/3

T = 11/6 miles


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Multiply or divide as indicated.(3x)^12 divided by (3x)^4

Help so lost and confused with this. Don't know where to start

Answers

This is the division property of exponents. When dividing to exponential with the same base, you subtract the exponents, the top minus the bottom. So the answer is (3x)^(12-4)=(3x)^8

Final answer:

The expression (3x)^12 / (3x)^4 simplifies to (3x)^8 according to the rules of exponents.

Explanation:

In mathematics, when you divide two expressions with the same base and both are raised to powers, you just subtract the exponents. The base here is (3x) and the exponents are 12 and 4, respectively.

So, from the rule of exponents, (3x)^12 / (3x)^4 simplifies to (3x)^(12-4) = (3x)^8. This is your final answer.

Learn more about Exponents here:

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What is the sum if the first 22 terms of the following series? 86 + 79 + 72 + 65 +58+...

Answers

seems to be an arythmetic sequence
Sn=[n(a1+an)]/2
where
Sn means sum of all terms up the nth term
n=number of terms
a1=first term
an=nth term

so from 86 to the 22th term is from a1 to a22

find teh sequence
miknus 7 each time
an=a1+d(n-1)
an=87-7(n-1)
find 22n term
a22=87-7(22-1)
a22=87-7(21)
a22=87-147
a22=-60

S22=[22(87-60)]/2
S22=[22(27)]/2
S22=594/2
S22=297

the sum is 297

The equation of line CD is (y − 3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?

Answers

The\ slope-point\ form:y-y_0=m(x-x_0)\ where\ m\ is\ a\ slope\n\nIf\ k:y=m_1x+b_1\ and\ l:y=m_2x+b_2\n\nk\perp l\iff m_1m_2=-1\to m_2=-(1)/(m_1)\n\ntherefore\nthe\ slope\ of\ line\ CD:y-3=-2(x-4)\ is\ m_1=-2\ and\ the\ slope\nof\ a\ line\ prpendicular\ to\ CD\ is\ m_2=-(1)/(-2)=(1)/(2)

Answer: 1/2
(y-3)=-2(x-4)
(y-3)= -2x+8
y= -2x+11
perpendicular slopes are always reciprocals and opposite so the slope would be
slope=1/2

What is 0.3 in a fraction?

Answers


When you're reading out loud and you come to  " 0.3 ",
you say "three tenths".

"Three tenths" is the fraction " 3/10 ".

A recent survey by the cancer society has shown that the probability that someone is a smoker is P(S)=0.19. They have also determined that the probability that someone has lung cancer, given that they are a smoker is P(LC|S)=0.158. What is the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S∩LC) ?0.35


0.03


0.02


0.83

Answers

Answer:

P (S∩LC) = 0.03

Step-by-step explanation:

We are given that the probability that someone is a smoker is P(S)=0.19 and the probability that someone has lung cancer, given that they are a smoker is P(LC|S)=0.158.

Given the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).

P (LC|S) = P (S∩LC) / P (S)

Substituting the given values to get:

0.158 = P(S∩LC) / 0.19

P (S∩LC) = 0.158 × 0.19 = 0.03

What is the product of d – 9 and 2d2 + 11d – 4?A=2d3 – 7d2 – 103d + 36
B=2d3 – 7d2 – 95d + 36
C=2d3 + 7d2 – 95d + 36
D=2d3 + 7d2 – 103d + 36

Answers

Answer:

2d^3-7d^2-103d+36

A is the correct option.

Step-by-step explanation:

We have to find the product

(d-9)(2d^2+11d-4)

Using the distributive property (term by term multiplication), we have

d\cdot2d^2+d\cdot11d+d\cdot(-4)-9\cdot2d^2-9\cdot11d-9\cdot(-4)

On multiplying, we get

2d^3+11d^2-4d-18d^2-99d+36

Combine like terms

2d^3-7d^2-103d+36

A is the correct option.

Answer:

(A)2d^3-7d^2-103d+36

Step-by-step explanation:

It is given that there are two functions that are (d-9) and 2d^2+11d-4 and

We have to find the product of (d-9) and 2d^2+11d-4, therefore we can write as:

(d-9)(2d^2+11d-4)

2d^3-18d^2+11d^2-99d-4d+36

2d^3-7d^2-103d+36

which is the required product.

Thus, Option A is correct.