Carla made a scale drawing of a classroom. The length of the classroom in the drawing is 5in. The actual length is 40ft. What scale did Carla use for her drawing?
Answers
Answer:
1/96
Step-by-step explanation:
scale is
a model cannot be as same size as that of actual object ,
hence objects are scales down to some value so that its model can be comfortably made.
scale is generally ratio of length of drawing and actual length of object
scale = length of drawing / actual length of object.
Given
length of classroom drawing = 5in
actual length of classroom = 40 ft
as unit of drawing and actual classroom is different lets make unit of class smilar to that of drawing that is in inches
we know
1 feet = 12 inches
thus 40 feet = 12*40 inches = 480 inches
thus,
actual length of classroom in inches = 480 inches
scale used by Carla = length of drawing / actual length of classroom
= 5 inches/480 inches = 1/96 (answer)
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Enter your answer in the box.
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y-ordinate of x-intercept is 0 .Putting y = 0 in the equation we get 1 3 x + 0 = − 15 or 1 3 x = − 15 or x = − ( 3 ⋅ 15 ) = − 45 ∴ x=intercept is ( − 45 , 0 ) graph{-1/3x-15 [-80, 80, -40, 40]}[Ans]
Hope this helped.
Your answer:
x-intercept is ( -45 , 0 )
Answer:
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cameras per day, what would their daily profit be?
Answers
Amount of money spent per day = $1800
Cost of overhead expenses per day for labor and materials = $9
Selling price of each camera = $18
a. Let us assume the number of cameras manufactured per day = x dollars
Then
Cost of cameras sold in 1 day = 18x
So
18x = 1800 + 9x
18x - 9x = 1800
9x = 1800
x = 200
From the above deduction, we can conclude that the number cameras sold per day is 200
b. Daily selling amount of 250 cameras = 250 * 18
= 4500 dollars
Daily manufacturing price of 250 cameras = 1800 + (9 * 250)
= 4050 dollars
Then
Daily profit = 4500 - 4050
= 450 dollars
Answers
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