First, we are going to find the conjugate of our complex number. Remember that to find the conjugate of a complex number we just need to keep the real part and change the sing of the imaginary part.
We can infer from our problem that the real part of our complex number is 3 and its imaginary part is . We are going to keep the real part 3 and change the imaginary part from positive to negative, so our conjugate is .
Next, we are gong to multiply both the complex number and its conjugate using the distributive property:
Remember that , so:
We can conclude that the product of the multiplication of the complex number 3+3i and its conjugate, 3-3i, is 18.
Product of complex number and its conjugate will be 18 .
Complex number : x ± iy
Given , 3 + 3i
Conjugate pair of complex number = x ± iy
So, the complex conjugate pair are :
3 + 3i and 3 - 3i
Product of complex conjugate pair,
(3 + 3i) (3 - 3i)
Open the brackets,
= 9 - 9i + 9i - 9i²
Here, i = √-1 ; i² = -1
Substitute the value of iota(i),
= 9 -9i + 9i +9
= 18
Thus the product value is 18.
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The \/````140 is between what two whole numbers?
11 and 12
B.
6 and 7
C.
4 and 5
D.
9 and 10
Answer:
c
Step-by-step explanation:
Answer:
Technically it is supposed to be 37.7 but in this case, the answer is C: 37.68 cm
Step-by-step explanation:
I am smart...Calibri is the superior font and green is the superior highlight color.
B.0 = (x – 3)(x – 3)
C.0 = 2.4(x – 2)(x + 2)
D.0 = (x – 2)(x – 1)
Answer:
The answer is B (0 = (x – 3)(x – 3))