The standard deviation of the sample mean differences is 16.98.
It is defined to be the square root of the population variance of the vector. The sample standard deviation s is defined to the square root of the sample variance of the vector.
The standard deviation of the sample mean differences should be calculated using the standard deviations of the two populations. In order to see how they differ, we need to first subtract them from each other, so: 21.2-17.6 = 3.6 We then divide this number with the first standard deviation as follows: 3.6/21.2 and multiply this answer by 100. Therefore, the standard deviation of the sample mean is 3.6/21.2 x 100 = 16.98.
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B. White blood cell
C. Stem cell
D. Liver cell
Answer:
C. Stem Cell
Explanation:
Because a specialized tissue cell is a stem cell and cells that are already specialized cannot go back to being a stem cell.
Assuming a diallelic gene exhibiting complete dominance, with tall plants being the dominant phenotype and short plants the recessive one, the cross of a heter0zyg0us plant with a short one results in a phenotypic ratio 1:1.
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We know that the cross involved a heter0zyg0us dominant tall pea plant and a short pea plant.
We will assume a diallelic gene coding for this trait, and exhibiting complete dominance. This means that the dominant allele completely masks the expression of the recessive allele.
So,
If the heter0zyg0us plant exhibits the dominant phenotype, it means that the allele coding for tall plants in the dominant allele.
So let us say that
According to this information, the tall plant is Tt and the short plant is tt.
So let us make the cross,
Cross: tall plant with short plant
Parentals) Tt x tt
Gametes) T t t t
Punnett square) T t
t Tt tt
t Tt tt
F1) Genotype
Genotypic ratio ⇒ 1:1
Phenotype
Phenotypic ratio ⇒ 1:1
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