Answer: C. lithium
Explanation:
Standard reduction potential is the tendency for an element to gain electrons or get reduced ,measured at standard conditions i.e. when concentration is 1 M and temperature is 298 K.
It is given by:
Thus lithium has the lowest tendency to accept electrons and thus has lowest standard reduction potential.
Answer:
50%
Explanation:
Genotypes T1T1, T1T2, and T1T3 all have the "T1" allele with 50, 60, and 40 individuals respectively.
add all the genotypes with the T1 allele and divide it by the total number of individuals.
(50+60+40)/(50+60+40+50+55+45)= .5= 50%
The option that best describes viruses is: Viruses are nonliving infectious agents. thus option A is correct.
A virus is an infectious agent of small size and simple composition that can multiply only in living cells of animals, plants, or bacteria.
Viruses cannot replicate on their own and they need a host cell in order to survive. Antibiotics kill bacteria but not viruses. Antivirals and vaccines are made available to decrease the production of viruses, but not totally stopping them. Bacteria and virus differ in so many ways. so, option A is correct.
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Answer:
Explanation:
Both conduction and convection need matter to transfer thermal energy.
Both only occur when currents are created by different densities.
Conduction involves collision of particles, while convection involves the movement of a liquid or gas.
or both only occur when currents are created by different densities.
(I tried my best to find the answer, let me know if this was helpful, goodluck!)
a. When crossing triply heterozygous flies (Aa Bb Cc), where each gene has one dominant allele and one recessive allele, the phenotypic ratios among the progeny would be 1:1. b. The genotype of the wild-type male can be deduced based on the phenotypic ratios observed in the crosses with the tester strains.
a. If you crossed triply heterozygous flies (Aa Bb Cc), where each gene has one dominant allele and one recessive allele, you can use the product rule to predict the phenotypic ratios among the progeny.
For each gene, the possible gametes are A and a, B and b, C and c. When you cross the triply heterozygous flies, you can determine the possible genotypes of the offspring:
Genotypes:
AA BB CC (wild type)
AA BB Cc (wild type)
AA Bb CC (wild type)
AA Bb Cc (wild type)
Aa BB CC (wild type)
Aa BB Cc (wild type)
Aa Bb CC (wild type)
Aa Bb Cc (wild type)
The phenotypic ratios can be determined by counting the number of wild-type (dominant phenotype) offspring and dividing it by the total number of offspring:
Wild-type progeny (AA BB CC, AA BB Cc, AA Bb CC, AA Bb Cc, Aa BB CC, Aa BB Cc, Aa Bb CC, Aa Bb Cc) = 8
Total number of progeny = 8 (since each possible genotype occurs once)
Phenotypic ratio: 8 wild-type : 8 total = 1:1
b. To determine the genotype of the wild-type male, we can deduce it based on the phenotypic ratios observed in the crosses with the tester strains.
In the cross with the tester strain AA bb cc, only 1/4 of the progeny are wild type. This means that the male being tested (wild-type male) must be heterozygous for the B and C genes (Aa Bb Cc) since the wild-type phenotype requires one dominant allele for each of the three genes.
In the crosses involving the other two tester strains (aa BB cc and aa bb CO), half of the progeny are wild type. This indicates that the wild-type male is homozygous for the A gene (AA Bb Cc) since the wild-type phenotype requires two dominant alleles for the A gene.
So, the genotype of the wild-type male is Aa BB Cc.
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Answer:
the genotype depends more on if its a boy or girl
Explanation: