A grocer stacks oranges in a four-sided pyramid that is 6 layers high. Solve for the number of oranges in the pile.A. 36
B. 546
C. 105
D. 91

Answers

Answer 1

Answer: Each layer contains the square of the layer number.
So,
Let's figure out :
1 squared = 1
2 squared = 4
3 squared = 9
4 squared = 16
5 squared = 25
6 squared = 36
Hence,
The total number of oranges in the pile = 1+4+9+16+25+36
= 91 oranges

D. 91

Answer 2

Answer:

The answer is 91.

The question is based on on a mathematical topic called ''Geometry'', and is simply asking for the total number of the oranges in the four-sided pyramid.

Further Explanation

In geometry, a pyramid is a polyhedron that is constructed when the polygonal base is connected to an iconic surface. The base edge and apex form a triangle that is called a lateral face. A pyramid can also be with an n-sided base that has n + 1 vertices, n + 1 faces, and 2n edges.

But the first thing to do is to get the number of oranges in each phases of the four-sided pyramid. To do this, we square the root the numbers of the vertices.

1 squared = 1 [for the first phase of the pyramid]

2 squared =4 [we got 4 as our answer for the second layer of the pyramid]

3 squared = 9 [9, for the third phase of pyramid]

4 squared = 16

5 squared = 25

6 squared = 36 [and 36 is the last in the pyramid]

The addition of the total oranges in each phase of the six layers is 91.

The total number of oranges in the pile = 1+4+9+16+25+36=91

KEYWORDS:

polygon
geometry
four-sided pyramid
polyhedron
triangle

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