Answer:
liquids
Explanation
664.2 km=____cm
(664.2 km) · (1,000 m/km) · (100 cm/m) =
(664.2 · 1,000 · 100) (km·m·cm/km·m) =
66,420,000 cm
For metric conversion, you can remember this acronym for help:
King Henry died unusually drinking chocolate milk. Which stand for:
Kilo - unit * 1000
Hecto - unit * 100
Deca - unit * 10
Unit - unit * 1
Deci - unit *
Centi - unit *
Milli - unit *
Kilometers and centimeters are five places apart apart, so you move the decimal point in 664.2 to the right five times, which means 664.2 km = 66420000 cm.
To avoid confusion on which direction to move the decimal point, imagine two shapes on each end of a scale. On each end, there is one large shape and one small shape. There has to be one of each on either side for it to balance. For this problem, a kilometer is a larger unit than a centimeter, so this means that the blank space needs to have a number greater than 664.2, or else the scale won't balance. Hope this helped.
Answer:
As the mass is not written well, i will use the equation in terms of the gravitational acceleration:
The equation for the period of a satellite is:
We want to find r, so isolating r we get:
Where:
T = period.
r = radius of the satellite.
R = radius of the planet.
g = gravitational acceleration of the planet.
pi = 3.14159...
g = 78999.64 mi/h^2 (value of a table)
T = 42.391 h.
R = 3958.8 miles
We can replace those values in the equation and get:
Now this value is measured from the center of the Earth, then the altitude of the satellite measured from the surface of the Earth will be:
H = r - R = 38,339.1mi - 3958.8mi = 34,380.3 mi
Answer:
for the body to float, the density of the body must be less than or equal to the density of the liquid.
Explanation:
For a block to float in a liquid, the thrust of the liquid must be greater than or equal to the weight of the block.
Weight is
W = mg
let's use the concept of density
ρ_body = m / V
m = ρ_body V
W = ρ_body V g
The thrust of the body is given by Archimedes' law
B = ρ_liquid g V_liquid
as the body floats the submerged volume of the liquid is less than or equal to the volume of the block
ρ_body V g = ρ_liquid g V_liquid
ρ_body = ρ liquid Vliquido / V_body
As we can see, for the body to float, the density of the body must be less than or equal to the density of the liquid.
b) 6.67x10-19hz
c) 3x108hz
d) 1.5hz
Show calculation
Answer:
1.5 x 10¹⁸hz
Explanation:
Given parameters:
Wavelength = 2 x 10⁻¹⁰m
Unknown:
Frequency = ?
Solution:
To find the frequency, use the expression below;
V = f x wavelength
V is the speed of light = 3 x 10⁸m/s
f is the frequency
Now;
Insert the parameters
3 x 10⁸ = 2 x 10⁻¹⁰ x frequency
Wavelength = = 1.5 x 10¹⁸hz