PHYSICS HIGH SCHOOL

A 120-V power supply connected to a 30-ohm resistor will produce
amps of current

Answers

Answer 1
Answer:

Answer:

4 amps

Explanation: ohms law

Related Questions

One student did an experiment on the rock cycle. The steps of the experiment are shown below. Collect five pieces of wax of different colors. Use a plastic knife to scrape off thin shavings of the pieces of wax. Pile the wax shavings of different colors one over the other. Hold the pile of wax shavings in the palm and squeeze it for two to three minutes. Fold the pile and squeeze it in the palm again for a minute. What does the student's experiment most likely demonstrate about the rock cycle? a. Weathering can change igneous rocks into sediments. b. Weathering can change metamorphic rocks into sediments. c. Heat and pressure can change igneous rocks into metamorphic rocks. d. Heat and pressure can change sedimentary rocks into metamorphic rocks.
The speed of light is closest to 300,000
To be considered acid rain, precipitation would have to
Leon sees a poster that shows a lake in front of a snow-capped mountain. The mountain appears upside down in the lake. Which best explains why the image of the mountain appears in the lake?A.The surface of the lake is smooth.B.The surface of the lake is transparent.C.The surface of the lake is polished.D.The surface of the lake is rough.
Compute the resistance in ohms of a lead block 15 cm long and 0.10 cm2 in cross-sectional area. (ρ = 2.2 x 10-5 ohm-cm)

To dry the brakes, drive slowly in __________ and apply light pressure on your brake pedal.

Answers

The answer is low gear. To dry the brakes of a vehicle, one must driv slowly in low gear and apply light pressure on the vehicle's brake pedal. Dry brakes are less expensive and are cheap when it needs replacement, yet under pressure they may cause more damage to the system than wet brakes, which are better in terms of emergency.

In scientific terms, how is power related to work? A.Power is the ability to do work.


B.Power is the force of work over a certain distance.


C.Power is the rate at which work is accomplished.


D.Power is the energy supplied in a force.

Answers

The answer is c. Hope this helps :)

A motorbike is traveling to the left with a speed of 27.0 m s 27.0 s m ​ 27, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when the rider slams on the brakes. The bike skids 41.5 m 41.5m41, point, 5, start text, m, end text with constant acceleration before it comes to a stop. What was the acceleration of the motorbike as it came to a stop?

Answers

Answer:

Explanation:

Initial velocity , u = 27 m/s

displacement before stop,  s = 41.5 m .

final velocity,  v = 0

acceleration a = ?

v² = u² + 2 a s

0 = 27² + 2 x a x 41.5

a = - 27² / 2 x 41.5

= - 8.78 m /s

Deimos completes one (circular) orbit of Mars in 1.26 days. The distance from Mars to Deimos is 2.35×107m. What is the centripetal acceleration of Deimos?

Answers

Answer:

The centripetal acceleration of Deimos is 0.077m/s^(2).

Explanation:

The centripetal acceleration is defined as:

a = (v^(2))/(r)   (1)

Where v is the velocity of Deimos and r is the orbital distance.        

Notice that is necessary to determine the velocity first.

The speed of the Deimos can be found by means of the Universal law of gravity:

F = G(M \cdot m)/(r^(2))  (2)

Then, replacing Newton's second law in equation 2 it is gotten:

m\cdot a = G(M \cdot m)/(r^(2))  (3)

However, a is the centripetal acceleration since Deimos almost describes a circular motion around Mars:

a = (v^(2))/(r)  (4)

Replacing equation 4 in equation 3 it is gotten:

m(v^(2))/(r) = G(M \cdot m)/(r^(2))

m \cdot v^(2) = G (M \cdot m)/(r^(2))r

m \cdot v^(2) = G (M \cdot m)/(r)

v^(2) = G (M \cdot m)/(rm)

v^(2) = G (M)/(r)

v = \sqrt{(G M)/(r)}  (5)

Where v is the orbital speed, G is the gravitational constant, M is the mass of Mars, and r is the orbital radius.    

v = \sqrt{((6.67x10^(-11)N.m^(2)/kg^(2))(6.39x10^(23)kg))/(2.35x10^(7)m)}

v = 1346m/s

Finally, equation 4 can be used:

a = ((1346m/s)^(2))/(2.35x10^(7)m)

a = 0.077m/s^(2)

Hence, the centripetal acceleration of Deimos is  0.077m/s^(2).

Final answer:

The centripetal acceleration of Deimos, one of Mars' moon, can be calculated using its orbital period and distance from Mars. Convert the time units to seconds and use the formulas for velocity and centripetal acceleration to get an answer of approximately 7.84x10^-5 m/s^2.

Explanation:

To find the centripetal acceleration of Deimos, we can use the formula for centripetal acceleration, which is a =v^2/r , where v is the velocity and r is the radius (distance from Mars to Deimos). The velocity can be found using the formula v = 2πr/T, where T is the period (time for one complete orbit).

First, convert the days into seconds because the SI unit of time in physics is second. So, 1.26 days = 1.26 * 24 * 60 * 60 = 108864 seconds.

Then, calculate the velocity: v = 2 * π * 2.35x10^7m / 108864s = 1.36 km/s.

Finally, substitute v and r into the centripetal acceleration formula: a = (1.36x10^3m/s)^2 / 2.35x10^7m = 7.84x10^-5 m/s^2.

The centripetal acceleration of Deimos is approximately 7.84x10^-5 m/s^2.

Learn more about Centripetal Acceleration here:

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The least common shape for a galaxy is ______. irregular elliptical cluster spiral spherical

Answers

Answer:  cluster

Explanation:

There are four main shapes of galaxies: spiral, galaxies are divided into four main groups: spiral, lenticular, elliptical, and irregular, elliptical, and irregular.

The least common shape is cluster

Spiral galaxies- These are the most common. These have arms extending from a bright bulge in spiral shape.

Elliptical galaxy have ellipsoidal shape.

Lenticular galaxies - Intermediate between elliptical and spiral galaxies.

Irregular shape- No well defined shape

Spherical - Nearly spherical galaxies. These are least

cluster- group of galaxies having irregular shape is the least common shape.

Question: The least common shape for a galaxy _____.

Answer:Cluster

How many seconds would an Olympic skier take to race down a 2500 meter course going 250 m/sec?

Answers

Answer:

10 seconds

Explanation:

Hope this is right and that it helps.

You see if the skier is going 250 meters a second 250 times 10 is 2500 so it would take the skier 10 seconds.

Answer:

10 sec.

Explanation:

distance = 2500 meters

velocity = 250 meter/second

time = distance / velocity

       =    2500 meters    

          250 meter/second

       = 10 sec.
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