Answer:
There is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same frequency.
Step-by-step explanation:
In this case we need to test whether there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same frequency.
A Chi-square test for goodness of fit will be used in this case.
The hypothesis can be defined as:
H₀: The observed frequencies are same as the expected frequencies.
Hₐ: The observed frequencies are not same as the expected frequencies.
The test statistic is given as follows:
The values are computed in the table.
The test statistic value is .
The degrees of freedom of the test is:
n - 1 = 12 - 1 = 11
Compute the p-value of the test as follows:
p-value < 0.00001
*Use a Chi-square table.
p-value < 0.00001 < α = 0.05.
So, the null hypothesis will be rejected at any significance level.
Thus, there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same frequency.
Answer:20 cm
Step-by-step explanation:
Volume of cone=540π
Radius=r=9
Volume of cone=1/3 x π x r^2 x h
540π=1/3 x π x 9^2 x h
540π=1/3 x π x 9 x 9 x h
540π=(1xπx9x9xh)/3
540π=(81πh)/3
540π=27πh
Divide both sides by 27π
540π/27π=(27πh)/27π
20=h
h=20
Height =20 cm
Answer:
12<|h-8|<22
Step-by-step explanation:
Answer:
-2
Step-by-step explanation:
-15+7y=-25+2y
7y-2y=-25+15
5y= -10
5y/5= -10/5
y= -2
Answer:
y= -17/5 or -3.4
Step-by-step explanation:
-8+7y= -25+2y
5y= -17
y= -17/5 or -3.4
Simplify your answer as much as possible.
Answer:
mixed number: 4 1/15
Exact: 61/15
The Quotient of two Rational Numbers is a Rational Number if and only if Numerator and Denominator are Multiples.
From Algebra, we know that a Rational Number is a Real Number of the form:
, , (1)
Where:
The Quotient can be an Integer or not. In the first case, all Quotients have their equivalent Rational Numbers.
Now, if we divide a Rational Number by another Rational Number, then we have the following expression:
If is a Rational Number, then it must also an Integer and if is an Integer, then and must be Multiples of each other.
The Quotient of two Rational Numbers is a Rational Number if and only if Numerator and Denominator are Multiples.
Please see this question related to Rational Numbers: brainly.com/question/24398433
Answer:
Yes,
Step-by-step explananation
The quotient of two rational numbers is always rational, and the reason for this lies in the fact that the product of two integers is always an rational number.
Step-by-step explanation:
Factor by grouping.
f(x) = x³ + 3x² − 5x − 4
f(x) = x³ + 3x² − 4x − x − 4
f(x) = x (x² + 3x − 4) − (x + 4)
f(x) = x (x − 1) (x + 4) − (x + 4)
f(x) = (x² − x) (x + 4) − (x + 4)
f(x) = (x² − x − 1) (x + 4)