What is the mode of the following numbers?8, 10, 8, 5, 4, 7, 5, 10, 88,10,8,5,4,7,5,10,88, comma, 10, comma, 8, comma, 5, comma, 4, comma, 7, comma, 5, comma, 10, comma, 8

Answers

Answer 1

Answer: The mode of this is 8,10, and 5

Answer 2

Answer:

The answer to this is 10 and 5

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Emily had 75 buttons. She gave 15 buttons to jake. What percentage of the buttons did Emily give to hair?

Answers

Emily gave Jake 20% of the buttons. 20% = 15 buttons, and 15 x 5 = 75

8 of the students went to see live animals what fraction part of the group is that

Answers

In order to answer that question we would have to know how many people are in the group
For example: if there are ten people in the group then the fraction would be 8/10
If there are 20 people in the group then the fraction would be 8/20
I hope this helped

To answer the question you need to know how many students n all are in the group then 8 would be the numerator and the number of all the students in the group would be the denominator

How many nickels are in 2.25

Answers

try getting rid of the decimal. then divide 225 by 5.
the answer will be 45 nickels

if you know that2 nickels are .then 10 + 10=100 ,you need 10 dimes to make $ 1.00 . $1.00 + $1.00 is $2.00 then just add $ 0.25 cent .

The definition of term

Answers

Hi there! A term would be a number or a variable. For example, an equation like 5x-8=6. 5x, 8, and 6 would be the terms.

a)postos pelo vértice b )adjacentes suplementares c ) congruentes e não opostos pelo vértice d )suplementares e não adjacentes

Answers

i can not read this because it is a different language sorry

Together, Sarah's two cats have the same mass as her dog, 11 kg. The mass of one cat is1500 g greater than the mass of the other. What are the masses of the two cats?

Answers

First, lets do all calculations in kg. 1kg=1000 grams
Lets set 1 cat's mass as x.
Lets set the other cat's mass as y.
1) x+y=11
2) y=x+1.5

Lets plug eq 2 into eq 1.
x+x+1.5=11
2x+1.5=11
2x=9.5
x=4.75 kg

If one cat weighs 4.75 kg, then the other must weigh 6.25 kg.

so cat1=x
cat2=y
x+y=11kg
11kg=11000g
x=y+1500
subsitute
y+1500+y=11000
subtract 1500
2y=9500
divide by 2
y=4750
subsitue
x=4750+1500
x=6250

one cat weighs 6250g and the other weighs 4750g

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Which steps could be used to solve this story problem? At the art store paint costs $5, brushes cost $3, and packs of pastel crayons cost $13. Kari bought 3 pots of paint, 4 brushes, and 3 packs of pastel crayons. How much money did Kari spend?A.Divide $13 ÷ 3. Then add $5 and 4. Then add the quotient and the sum together and subtract 3.B.Add $5 and 3. Then add $3 and 4. Then add $13 and 3. Then add the 3 sums together.C.Multiply $5 × 3. Then multiply $3 by 4. Then multiply $13 by 3. Then add the products together.D.Subtract 3 from $13. Then subtract $3 from 4. Add the two differences together and multiply by $5.