Ms Smith has 28 sixth graders and 35 seventh graders
she wants to break them down into groups with each group having the same number of students from each grade
for this we have to find the highest common factor of 28 and 35 to see by which both 28 and 35 are divisible by
factors of 28 and 35 are as follows
28 - 1,2,4,7,14,28
35 - 1,5,7,35
the highest common factor both numbers is 7
therefore Ms Smith can break them down into 7 groups
each group will have
28 / 7 = 4 sixth graders
35 / 7 = 5 seventh graders
so each group will have 4 sixth graders and 5 seventh graders
so in each group there will be 4 + 5 = 9 students
she will break them down into 7 groups
each group has 9 students
Let m be my age in years.If s is my son's age in years, then my son is 52s weeks old. If g is mygrandson's age in years, then my grandson is 365g days old. Thus,
365g = 52s.
Since my grandsonis 12g months old,
12g = m.
Since my grandson,my son and I together are 120 years,
g + s + m = 120.
The above system of3 equations in 3 unknowns (g, s and m) can be solved as follows.
m / 12 + 365 m /(52 x 12) + m = 120 or
52 m + 365 m + 624m = 624 x 120 or
m = 624 x 120 /1041 = 72.
So, I am 72 yearsold.
The problem is hard...i don't know if you understood this..Hope i helped!
Answer:
y = 4x + 6
Step-by-step explanation:
2 = 4[-1] + b
-4
6 = b
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