Answer: Answer is 3/8 cup (or 1/4 cup plus 1/8 cup) There are all sorts of ways to figure this out. Here is one: 1/2 x 3/4 = 3/8
Answer:
(1) equilateral triangle
Step-by-step explanation:
Firstly, we will find all angles of triangle BCD
we are given
m<C=60
m<A=35
m<ABD=25
we know that sum of all angles in any triangle is 180
so, we get
m<A +m<ABD+m<DBC+m<C=180
we can plug values
35+25+m<DBC+60=180
m<DBC=180-120
m<DBC=60
now, we can find other angle
m<DBC+m<C+m<CDB=180
now, we can plug values
60+60+m<CDB=180
m<CDB=180-120
m<CDB=60
So, we can see that
m<C=m<DBC=m<CDB=60
so, all angles are equal
so, triangle BCD is an equilateral triangle
Martha estimated there were 95 marbles in a jar for a contest. The actual number of marbles in the jar was 117. What was the percent error of Martha's estimation?
22%
81.20%
23.16%
18.80%
Distributive property: a(b + c) = ab + ac
4n - 2 - 2n = 2(2n - 1 - n)
4n - 2 - 2n = 2n - 2 = 2(n - 1)
Answer:
a. 1 =ST; 20 = RS;5 = x
b. 40 = ST; 20 = RS; 12 = x
c.17 = RT;6 = RS; 7 = x
d. 34 = RT; 15 = RS; 6 = x
Step-by-step explanation:
___
Since the exercise ONLY tells you that PointSis inbetweenRT,use the SegmentAdditionPostulate for all exercises:
d.8x - 14 = 19 + [4x - 9]
8x - 14 = 10+ 4x(Combine like-terms)
- 8x-8x
___________________
-14 = 10 - 4x
-10-10
_____________
-24 = -4x
________
-4-4
6 = x[Plug this back into the equations above to get these measures: 34 = RT; 15 =RS]
c.x+ 10 = 11 + [2x - 8]
x+10 = 3+ 2x(Combine like-terms)
-2x-2x
________________
-x + 10 = 3
- 10-10
___________
-x= -7
____
-1-1
x = 7 [Plug this back into the equations above to get these measures: 17 = RT; 6 = RS]
b.60 = [4x - 8] + [3x - 16]
60 = 7x-24(Combine like-terms)
+24+ 24
______________
84 = 7x
______
77
12 = x[Plug this back into the equations above to get these measures: 40 = ST; 20 = RS]
a.21 = [x - 4] + [2x + 10]
21 = 3x+6(Combine like-terms)
-6- 6
______________
15 = 3x
______
33
5 = x[Plug this back into the equations above to get these measures: 1 = ST; 20 = RS]
I am delighted to assist you anytime.
To solve for x and find the lengths RS, ST, and RT, we can set up an equation using the given information. Using the equation RS + ST + RT = 0 and substituting the given values, we can simplify the equation to find x. With the value of x, we can then find the lengths RS, ST, and RT. Therefore, RS = -8, ST = -13, and RT = 21.
To write an equation in terms of x, we need to set up an equation using the given information RS = 2x + 10, ST = x - 4, and RT = 21.
We can start by writing the equation RS + ST + RT = 0.
Substituting the given values, we get (2x + 10) + (x - 4) + 21 = 0. Simplifying this equation, we have 3x + 27 = 0.
Solving for x, we subtract 27 from both sides and divide by 3, to get x = -9.
With the value of x, we can now find the lengths RS, ST, and RT. RS = 2(-9) + 10 = -8, ST = (-9) - 4 = -13, and RT = 21.
Therefore, RS = -8, ST = -13, and RT = 21.
For more such questions on equations, click on:
#SPJ2