Five less than a number is at least -28

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Answer 1

Answer: Five less than a number is at least -28

n-the number

n - 5 < -28 |add 5 to both sides
n < -23

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A model of a famous statue is 2 1/2 inches tall the actual statue is six and two thirds feet tall what is the ratio of the height of the model to the height of the actual statue in simplest form

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Solve the system of equations x - 2y = 2 and 3x - 5y = 9 by writing and solving a matrix equation. Show all your work.

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we solve X simultenously
x - 2y =2................equation 1
3x - 5y =9.............equation 2
find urself third equation frm dis two equations
x = 2+2y...........equation 3
SUB: 3 IN 2
3(2+2y)-5y =9
solve y
6+6y-5y=9
6y-5y=9-6
1y=3
divide both side by 1
therefore Y=3

SUB:Y=3 IN EQUATION 3
x=2+2(3)
x=8

Find an equation of the line satisfying the given conditions

Through (6,4); perpendicular to 3X + 5Y =38

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To answer this, we will need to know:

• The slope of the equation we are trying to get
• The point it passes through using the

First, we will need to find the slope of this equation. To find this, we must simplify the equation $3x+5y=38$ into $y=mx+b$ form. Lets do it!

$3x+5y=38$
= $5y = -3x+38$ (Subtract 3x from both sides)
= $y= -(3)/(5)x+ (38)/(5)$ (Divide both sides by 5)

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is $(5)/(3)$ .

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

$(y-y _(1) )/(x- x_(1) )=m$

Substituting values, we find that:

$(y-4)/(x-6)= (5)/(3)$

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that:

$y= (5)/(3)x-6$ , which is our final answer.

Thank you, and I wish you luck.

$(6,4); 3x + 5y =38 \ subtract \ 3x \ from \ each \ side \n \n 5y = -3x + 8 \ divide \ each \term \ by \ 5 \n \n y = -\frac{3} {5}x + (38)/(5)\n \n The \ slope \ is :m _(1) = - (3)/(5) \n \n If \ m_(1) \ and \ m _(2) \ are \ the \ gradients \ of \ two \ perpendicular \n \n lines \ we \ have \ m _(1)*m _(2) = -1$

$m _(1) \cdot m _(2) = -1 \n \n -(3)/(5) \cdot m_(2)=-1 \ \ / \cdot (-(5)/(3)) \n \n m_(2)=(5)/(3)$

$Now \ your \ equation \ of \ line \ passing \ through \ (6,4) would \ be: \n \n y=m_(2)x+b \n \n4=(5)/(\not3^1) \cdot \not 6^2 + b$

$4=5 \cdot 2+b\n \n4=10+b \n \nb=4-10\n \nb=-6 \n \n y = (5)/(3)x -6$

What is the measure of DC