1.the typical school lunch milk carton is a half pint. how many ounces is this?2.you need a quart of water but you only have a measuring cup. how many times do you need to fill the cup in order to get a quart?

3.what is the speed of a car in feet/second that is traveling 60 miles/hour?

Answers

Answer 1
Answer: 1 pint = 16 ounces
1/2 pint = 16/2 = 8 ounces.

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Find the equation lines(4, 5)(7, 3)

Factor completely and then place the factors in the proper location on the grid.a 2 - a - 20

Answers

Answer:

The correct answer is (a+4)(a-5)

Step-by-step explanation:

We have the polynomial a^2-a-20

For the polynomials of the form ax^2+bx+c we have to rewrite the middle term as a sum of two terms whose product is, in this case, a.c=-20 and whose sum is b=(-1).

a^2-a-20=\na^2+(-5+4)(a)-20=\n=a^2-5a+4a-20

Because b=(-5)+4=(-1) and a.c=(-5).4=(-20)

Now we have to factor by grouping:

a^2-5a+4a-20=\n(a^2+4a)-(5a+20)=\na(a+4)-5(a+4)=\n=(a-5)(a+4)

Then, the correct answer is (a+4)(a-5)

The fully factored form of this expression would be
(A-5)(A+4).

Suppose AP = 2 cm and BQ = 7 cm. What is the length of PC?

Answers

Step-by-step explanation:

is this a quadrilateral? or polygon or triangle?

what are the angles (I believe there should be at least an angle given) else PC can be any value that is positive

a long distance telephone company charges a rate of 8 cents per minute or 90 cent mininum charge per call, whichever is greater. Find the cost in cents per minute for a 41 minute call.

Answers

The cost of a 41 min call would be 328 cents. So, that would be 8 cents per minute, because the charge of the call is greater that 90 cents. Hope that helps!!

The three cards below form a number pattern

Answers

You do not have a picture inserted it is just a grey screen

Flyball is a relay race for dogs. In each of the four legs of the relay, a dog jumps over hurdles, retrieves a ball from a fly box, and runs back over the hurdles. The distance of the relay race is 51 feet. The collie starts the course 0.3 second before the sheepdog. The collie is running 23.4 feet per second while the sheepdog is running 24 feet per second. a. Let t represent the time (in seconds) it takes the collie to un the last leg . Write and solve an equation to find the number of seconds after which the sheepdog would catch up with the collie.

Answers

It would take 11.7 seconds for the sheepdog to catch up with the collie.

To determine the number of seconds after which the sheepdog would catch up with the collie, knowing that the distance of the relay race is 51 feet, and the collie starts the course 0.3 second before the sheepdog, and the collie is running 23.4 feet per second, while the sheepdog is running 24 feet per second, the following calculation must be performed:

  • (23.4 x 0.3) = 7.02
  • 24 - 23.4 = 0.6
  • 7.02 + 23.4X = Y
  • 24X = Y
  • 7.02 / 0.6 = 11.7
  • 7.02 + 23.4 x 11.7 = 280.8
  • 24 x 11.7 = 280.8

Therefore, it would take 11.7 seconds for the sheepdog to catch up with the collie.

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Solve for x. ax+bx=21

Answers

ax + bx = 21

factor out x

x(a + b) = 21
x = 21/(a+b)
ax+bx =21
on factorising x, we get
x( a+b) =21
x = 21/a+b