A substance that contains more hydroxide ions than hydronium ions in solution could have which pH value that would be greater than seven.
The chemical compound is a combination of two or more either similar or dissimilar chemical elements
For example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.
A material with a pH greater than 7 could have a solution with more hydroxide ions than hydronium ions. As pH levels over 7 signify that a solution is no longer neutral, it has the same number of hydrogen ions as OH ions but more hydroxide ions than hydrogen ions. because it is simpler.
Thus, a substance that contains more hydroxide ions than hydronium ions in solution could have which pH value that would be greater than seven.
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b) The wavelength doubles
c) The speed of the wave doubles
d) The wavelength is cut in half
e) The speed of the wave is cut in half
Doubling the frequency of a transverse wave on a string would result in the wavelength of the wave being halved. This is due to the inverse relationship between frequency and wavelength in the context of wave speed remaining constant.
When considering a transverse wave travelling on a string, if the frequency is suddenly doubled, then the wavelength would be cut in half rather than any other given option. This is because the speed of a wave is determined by the medium through which it travels—in this case, the string—rather than its frequency or amplitude. Because the speed remains constant when the frequency doubles, the only factor left to adjust is the wavelength, according to the wave speed equation 'v = fλ', where 'v' is wave speed, 'f' is frequency, and 'λ' is wavelength. Thus, frequency and wavelength have an inverse relationship: if frequency increases (doubles, in this case), wavelength must decrease (halve) to maintain the constant wave speed.
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Answer:
As the projectile starts it’s motion from a vertical height at y=10m, it’s vertical motion may be described as under-
y= 10+ut-0.5gt^2
Where “u” is initial vertical velocity
= 45 sin60,
“g” is acceleration due to the gravity (10m/sec^2)
and “t” is time.
When the projectile touches the ground the vertical height “y”=0
Therefore the time “t” taken for the flight of the projectile till it touches the ground may be calculated from the above equation when y=0 as under -
0= 10+45sin60 x t- 0.5x10 t^2
0= 10+45x (√3/2)x t-5 t^2
t^2-9x (√3/2)x t-2 =0
t= [4.5√3 + √(243/4+4)]/2
t=[7.794+ 8.047]/2
t= 7.92 sec.
The horizontal distance travelled during this time=
vt
Where “v” is horizontal velocity = 45 cos60.
Therefore,
vt =45cos60 x 7.92
= 45x0.5x7.92
= 178.2 m
I just got %100 on my quiz, the answer is d(wind flow and temperature
Answer:
The horizontal distance is 136.6 m.
Explanation:
Given that,
Initial speed = 38 m/s
Angle = 34°
Suppose, Calculate the horizontal distance in meters the ball has traveled when it returns to ground level.
We need to calculate the horizontal distance
Using formula of range
Where, v= speed
g = acceleration due to gravity
Put the value into the formula
Hence, The horizontal distance is 136.6 m.