Describe a real world situation for 40/h
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Answer:
1) Assume that you covered the distance of 40 miles in "h" hours by bicycle. You need to find speed. So. speed = tex]\frac{40}{h}[/tex]
2) Assume that you have 40 pens, you wanted to give your "h" number of friends equally. The number of pens each will get
Step-by-step explanation:
Case 1:
Assume that you covered the distance of 40 miles in "h" hours by bicycle. You need to find speed.
Distance = Speed*time
Speed =
We know the distance covered = 40 and time = h
Speed =
Case 2:
Assume that you have 40 pens, you wanted to give your "h" number of friends equally. The number of pens each will get
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What is 9 times 3/4?
Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(-1, 1) and Q(5,9)
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Answer:
ummm is there more to the problem?!
Cool.... the question???
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-5x = 4 Divide both sides by -5
x = -4/5
... That is the answer I got for x...
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Quadrant I
Quadrant II
Quadrant III
Quadrant IV
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The coordinates in a graph indicate the location of a point with respect to the x-axis and y-axis.
The coordinate (-3, 5) is located in QuadrantII.
Option B is the correct answer.
What are coordinates in a graph?
The coordinates in a graph indicate the location of a point with respect to the x-axis and y-axis.
The coordinates in a graph show the relationship between the information plotted on the given x-axis and y-axis.
We have,
(-3, 5)
We need to see which quadrant the given point (-3, 5() is located.
We know that we have four Quadrants:
Quadrant I:
The coordinates are in the form of (x, y).
Quadrant II:
The coordinates are in the form of (-x, y).
Quadrant III:
The coordinates are in the form of (-x, -y).
Quadrant IV:
The coordinates are in the form of (x, -y).
The coordinate (-3, 5) is in the Quadrant II
Thus,
The coordinate (-3, 5) is located in QuadrantII.
Option B is the correct answer.
Learn more about coordinates here:
#SPJ5
3y 2 z(2y 2 z + 4yz - y + z)
Answers
Answer: 48(y*z)^2 - 6z*y^2 - 6y*z^2
Step-by-step explanation: We want to find the product:
3y*2z*(2y*2z + 4yz - y - z)
First, distribute the product:
3y*2z*2y*2z + 3y*2z*4yz -*3y*2z*y - 3y*2z*z
now, let's simplify the equation:
(3*2*2*2)(y*z)^2 + (3*2*4)(y*z)^2 - (3*2)z*y^2 - (3*2)y*z^2
24(y*z)^2 + 24(y*z)^2 - 6z*y^2 - 6y*z^2
48(y*z)^2 - 6z*y^2 - 6y*z^2
If the equation you want to distribute is:
(3y^2z)*(2y^2z + 4yz - y - z)
the distribution is:
(3y^2z)´*(2y^2z) + (3y^2z)*4yz -(3y^2z)*y - (3y^2z)*z
6y^4z + 12y^(2z + 1)*z - 3y^(3z + 1) - (3y^2z)*z
=6y^(4z)+12y^(1+2z)z-3y^(1+2z)+3zy^(2z)