Gallium-69, an isotope of Gallium, contains 31 protons, 31 electrons and 38 neutrons.
Gallium-69 is a specific isotope of the element Gallium.Gallium is the element with atomic number 31 on the periodic table. This atomic number means that a Gallium atom has 31 protons in its nucleus. Given that in a neutral atom the number of electrons equals the number of protons, we can also deduce that Gallium-69 contains 31 electrons.
The number following the name of the element, 69 in this case, is the isotope's mass number, which is the total number of protons and neutrons that an atom of that isotope contains in its nucleus. To find the number of neutrons in Gallium-69, you simply subtract the number of protons from the mass number. This yields 69 - 31 = 38. Thus, Gallium-69 has 38 neutrons.
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The field of physics known as calorimetry determines how much heat is transferred during a chemical or physical process.
It requires precisely calculating the heat transport in a system using a calorimeter, a specialist tool. Two substances coming into contact at differing temperatures normally causes heat exchange to occur until thermal equilibrium is attained. The amount of heat transported can be determined by monitoring the temperature change and taking into account the individual heat capacity of the substances involved. Calorimetry has many uses, including figuring out how much energy is in food, researching chemical processes, and looking at the thermal characteristics of various materials. It is necessary to comprehend how energy is transformed in distinct systems.
To know more about calorimetry, here
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Using the combined gas law, we find that the new pressure of the gas sample, after it's compressed and heated, is approximately 353.8 kPa.
The subject of this question is gas laws, specifically the combined gas law which states that the ratio of the product of pressure and volume and the absolute temperature of a gas is constant. We apply this law to calculate the new pressure of the gas sample. Starting from the conditions of STP (Standard Temperature and Pressure, defined as 273.15 K and 1 atm i.e., 101.325 kPa), the volume of gas is decreased from 700.0 mL to 200.0 mL and the temperature is increased from 273.15 K to 30.0 degrees Celsius (or 303.15 K in absolute terms).
We set up the equation P1*V1/T1 = P2*V2/T2, where P1 = 101.325 kPa, V1 = 700.0 mL, T1 = 273.15 K, V2 = 200.0 mL, and T2 = 303.15 K. Plugging in these numbers and solving for P2 (the new pressure), we get P2 = P1*V1*T2 / (T1*V2) = 101.325 kPa * 700.0 mL * 303.15 K / (273.15 K * 200.0 mL) = approximately 353.8 kPa.
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Answer:
D. 33/16S please follow up me and give a thanks for my answer
B. The subscript 2 indicates that two atoms of oxygen are present in the substance.
C. The chemical symbol Al indicates that oxygen is present in the substance.
D. The subscript 2 indicates that two atoms of aluminum are present in the substance
In the formula Al2O3, the subscript 2 indicates the presence of two atoms of Aluminium, and the subscript 3 indicates the presence of three atoms of Oxygen.
The formula Al2O3 is for aluminium oxide. The coefficient and subscript in this formula tell us about the number of atoms of each element present in the compound. In this case:
So, the correct answer to the question is, the subscript 2 indicates that two atoms of aluminum are present in the substance (option D).
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the sum of the enthalpy changes of the intermediate reactions.
the product of the enthalpy changes of the intermediate reactions.
the fraction of the individual enthalpies of the intermediate reactions.
Answer : The correct option is, the sum of the enthalpy changes of the intermediate reactions.
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
For example :
The formation reaction of CO will be,
The intermediate balanced chemical reaction will be,
(1)
(2)
The expression for enthalpy of formation of CO is,
where,
n = number of moles
By adding reaction 1 and reverse reaction of reaction 2, we get the enthalpy of formation of CO.
Hence, the correct option is, the sum of the enthalpy changes of the intermediate reactions.