How can you determine if a point is a solution to a system of linear equations?
Please Help!

Answers

Answer 1
Answer:

Answer:

You can substitute the x value of coordinate (x,y) in the equation. If the outcome = the y value in the coordinate (x,y), then you have determined it to be on the system of linear equations.

Step-by-step explanation:

Point P has a coordinates: ( Px , Py ).

You can choose which value is easy to substitute. Eighter start with the Py or you could start with the Px. It could save you time if you pick the right one for the job.

If you want to verify if any point is valid in any (linear) equation(s), you can:

a) substitute the x value of coordinate (x,y) in the equation, and if the outcome has the same value as y in the coordinate (x,y), then that point is a valid solution of the (linear) equation.

b) substitute the y value of coordinate (x,y) in the equation, and if the outcome has the same value as x in the coordinate (x,y), then that point is a valid solution of the (linear) equation.

Answer 2
Answer:

Answer:

You can substitute the x value into the equation if the answer for y is the same for the y coordinate you will have your answer.

Step-by-step explanation:


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John threw a surprise birthday party for his friend. Food, drinks, and a DJ cost $480 for a group of 32 people. Write and solve and equation to find the cost c per person.

Answers

The required cost per person at the party is given as $15.

What is simplification?

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
John threw a surprise birthday party for his friend.
Let the cost per peroson be c,
According to the question,
32c = 480
c = 480 / 32
c = 15

Thus, the required cost per person at the party is given as $15.

Learn more about simplification here:

brainly.com/question/12501526

#SPJ2

First, you have to do 480/32. (divide) That gives you the cost of $15 per person.

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Answers

Answer:

there is nothing there

Step-by-step explanation:

literally

Answe    

Step-by-step explanation:

Escreva no caderno dois exemplos de números reais que obedecem a cada uma das condições A) números irracionais maiores que 2,5 e menores que 3.
B) números racionais maiores que -7/8 e menores que -3/4

Answers

A números irracionais maiores que 3,5 é menores que 3

F(x)= -2x^2 +8x -12 in vertex form

Answers

            f(x) = -2x² + 8x - 12
               y = -2x² + 8x - 12
          + 12                  + 12
       y + 12 = -2x² + 8x
y + 12 - 8 = -2x² + 8x - 8
        y - 4 = -2(x²) - 2(-4x) - 2(4)
        y - 4 = -2(x² - 4x + 4)
        y - 4 = -2(x² - 2x - 2x + 4)
        y - 4 = -2[x(x) - x(2) - 2(x) - 2(-2)]
        y - 4 = -2[x(x - 2) - 2(x - 2)]
        y - 4 = -2(x - 2)(x - 2)
        y - 4 = -2(x - 2)²
          + 4         + 4
             y = -2(x - 2)² + 4

-7 2/3 as an improper fraction

Answers

this one is tricky but don't mind the sign just yet

first you multiply 7 by 3 then add 2

21+2=23

now you can add the sign on 23/3 which gives us the answer of -23/3

The Kahn's Family lives in a house that has a backyard in the shape of an isosceles trapezoid and a triangle. The area of the backyard can be expressed as the sum of the area of the triangle and the area of the trapezoid, which is 1/2bh+1/2(p+q)L The base and the height of the triangle are represented by b and h, respectively. The bases of the trapezoid are p and q, and the height of the trapezoid is L. 2 Rearrange the formula to find the length of base as a function of the lengths of the other sections of the backyard.

Answers

This is solved the way any 2-step linear equation is solved:

  1. subtract the term not containing the variable of interest, then
  2. divide by the coefficient of that variable.

... A = (1/2)bh + (1/2)(p+q)L

... A - (1/2)(p+q)L = (1/2)bh . . . . . subtract the term on the right

... (A -(1/2)(p+q)L)/(1/2·h) = b . . . .divide by (1/2)h, the coefficient of b

... b = (2A -(p+q)L)/h . . . . . . . . . . simplify