Answer:
Here is the correct table:
x y
1 16
2 8
3 3
4 1
Answer:
G(t) = 1800(1.067)^t
Step-by-step explanation:
Answer:
G(t) = 1800(1.067)^t
Step-by-step explanation:
B)h(t) = (-16t2 + 3)/2
C)h(t) = -16(t/2)2 + 3
D)h(t) = -8(t)2 + 3
The correct function that describes the height of the ball on a replay that runs at half speed is h(t) = -16(t/2)^2 + 3. This is because the time in the original function enters as a square, so it must be halved before being squared.
In this problem, a slow motion replay means the time factor is slowed down by a half. The original function is h(t) = -16t2 + 3. However, the time factor isn't just halved, it's halved before being squared, because time enters the function as a square. So in the replay function, every instance of t in the original function is replaced with 0.5t or t/2. Hence, the correct option that describes the height of the ball in the replay is h(t) = -16(t/2)2 + 3.
#SPJ11
Answer: A
Step-by-step explanation: Simple Interest: A = P(1+rt)
P: the principal, the amount invested
A: the new balance
t: the time
r: the rate, (in decimal form)
Ex1: If $1000 is invested now with simple interest of 8% per year. Find the new amount after two years.
P = $1000, t = 2 years, r = 0.08.
A = 1000(1+0.08(2)) = 1000(1.16) = 1160