The weight that should be written as the mixed number should be
Given that,
Here we need to find out the weight that should be written as the mixed number.
So first we have to understand what is the mixed number i.e. described below.
A mixed number should be the mix of the whole number & the fraction.
So, the weight written as the mixed number should be
Learn more about the number here: brainly.com/question/17429689
B) -19
C) -√13-6
D)-2√13-6
E)2√13-6
Answer:
A and C
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
4x2+48x+144=52
Step 2: Subtract 52 from both sides.
4x2+48x+144−52=52−52
4x2+48x+92=0
For this equation: a=4, b=48, c=92
4x2+48x+92=0
Step 3: Use quadratic formula with a=4, b=48, c=92.
x=−48±√832/8
x=−6+√13 or x=−6−√13
b. f(x)=x^3+2x^2-5x-6
c. f(x)=x^3+4x^2-3x-18
d. f(x)=x^2+x-6
Answer:b
Step-by-step explanation:
f(x)=x^3+2x^2-5x-6
Put x= -3 in the equation
f(-3)=-3^3+2*3^2-5*3-6
= -27+18+15-6= 0
f(2)= 2^3+2*2^2-5*2-6
=8+8-10-6= 0
I am thinking that the quadrilateral is not given to be a rhombus.
The perimeter is the sum of the 4 sides.
Adding 2x^2 + x -1 to 3x^2 -5x and then that sum to 4x^2 gives
9x^2 - 4x - 1 as the sum of the three given sides.
Subtract that from the given perimeter to get the missing side length.
5x^2 + 2x + 1 - (9x^2 -4x -1) =
-4x^2 + 6x + 2
So answer is C.
Hmm first I'll check the slanted line cutting 2nd quardrant..
some points on this line are (-3,0),(0,3),(2,5),(3,6),etc.
Testing (-3,0)=(x,y):
y=-3+3=0 (true)..comparable with y=x+3
Testing (2,5)=(x,y):
y=2+3=5 (true)..comparable with y=x+3
Since this line bounds the value within some limits less than or equal to x+3(see graph you can see it clearly)...so it can be represented by y<=x+3.
Similarly for next line cutting 1st and 4th quardrant,
Points: (0,-4),(1,-1),(2,2),etc..
Testing (0,-4)=(x,y):
y=3*0-4=-4(true)...comparable with y=3x-4
Testing (1,-1)=(x,y):
y=3*1-4=-1(true)...comparable with y=3x-4
This line bounds within the region y>3x-4
NOTE:
1)If the region is bounded by solid line(line without dot) then you write inequality as y<=something or y>= something.
2)If the region is bounded by dotted line(line withdot) then you write inequality as y<something or y> something.
Hope this helps!