Answer:
Behavioral adaptation
Explanation:
There are mainly three types of adaptation seen in an organism that are structural, physiological, and behavioral adaptation. Structural adaptation is mainly physical adaptation in some structures of the organism like teeth are different in different organisms according to the food they eat.
Physiological adaptation is the adaption occurs due to change in the external stimuli in physiology of an organism. Behavioral adaptation is the adaptation that helps organism to survive in their environment. Their behavior can be learned or present from birth.
Spittlebugs release foam to hide in branches is an example of behavioral adaptation because this is the instinct of spittlebugs which protects them from predators and helps it to survive in its habitat.
So it is in the behavior of spittlebugs to release foam when it feels a threat and when it does not feel threat it does not form the foam.
Answer:
Animal cell that does not have a cell wall.
Explanation:
Thus the animal cell does not have a cell wall.
B - black (both BB and Bb genotypes)
b - albino (bb genotype)
This is a problem showing that 1 phenotype (black color) can be the result of two different genotypes (BB and Bb). These two crosses would be the equivalent of test crosses to determine genotype.
A black guinea pig crossed with an albino guinea pig produced 12 black offspring. This is the result (all black offspring) you would expect when breeding two true breeders (Two homozygotes BB x bb).
B B
b Bb Bb
b Bb Bb
When the albino was crossed with a second black one, 7 blacks and 5 albinos were obtained. This looks like the results you would expect between a heterozygote and an albino (Bb x bb).
B b
b Bb bb
b Bb bb
Answer:
A black guinea pig crossed with an albino guinea pig producing 12 black offspring
b b
B Bb Bb
B Bb Bb
The genotype of the black gunea pig will be BB in this situation and the genotype for the albino pig would be bb.
The gametes formed will be B, B,b, b.
The offsprings will have genotype Bb. They will be heterozygous black.
When the albino was crossed with a second black one, 7 blacks and 5 albinos were obtained
b b
B Bb Bb
b bb bb
The genotype of the black parent will be heterozygous i.e Bb in this condition. The genotype of the albino parent will be bb.
The gametes formed will be B,b,b,b.
50% of the offsprings will have the probability of having heterozygous Bb genotype. 50% of the offsprings will have the probability of having albino bb genotype.