The dimensions that give the maximum area is 5 cm by 5 cm.
Given:
The perimeter of this rectangle is 20 cm, and formula for perimeter is
P= 2(W+L)
P = 20 cm = 2W + 2L.
Then W + L = 10 cm,
or W = (10 cm) - L.
The area of the rectangle is A = L·W, and is to be maximized.
On substituting the values, we get A = L[ (10 cm) - L ], or A = 10L - L²
Note that this is the equation of a parabola that opens down. With coefficients a = -1, b = 10 and C = 0, we find that the x-coordinate of the vertex (which is the x-coordinate of the maximum as well) is
x = -b / (2a). Subbing 10 for b and -1 for a, we get:
x = -[10] / [2·(-1)] = 10/2, or 5.
This tells us that one dimension of the rectangle is 5 cm.
Since P = 20 cm = 2L + 2W, and if we let L = 5 cm, we get:
20 cm = 2(5 cm) + 2W, or
10 cm = W + 5 cm, or W = 5 cm.
Therefore, choosing L = 5 cm and W = 5 cm results in a square, which in turn leads to the rectangle having the maximum possible area.
Learn more:
Answer:
5 cm by 5 cm
Step-by-step explanation:
The perimeter of this rectangle is 20 cm, and the relevant formula is
P = 20 cm = 2W + 2L. Then W + L = 10 cm, or W = (10 cm) - L.
The area of the rectangle is A = L·W, and is to be maximized. Subbing (10 cm) - L for W, we get A = L[ (10 cm) - L ], or A = 10L - L²
Note that this is the equation of a parabola that opens down. With coefficients a = -1, b = 10 and C = 0, we find that the x-coordinate of the vertex (which is the x-coordinate of the maximum as well) is
x = -b / (2a). Subbing 10 for b and -1 for a, we get:
x = -[10] / [2·(-1)] = 10/2, or 5.
This tells us that one dimension of the rectangle is 5 cm.
Since P = 20 cm = 2L + 2W, and if we let L = 5 cm, we get:
20 cm = 2(5 cm) + 2W, or
10 cm = W + 5 cm, or W = 5 cm.
Thus, choosing L = 5 cm and W = 5 cm results in a square, which in turn leads to the rectangle having the maximum possible area.
Line D: y = 3x + 2
Which of the following shows the solution to the system of equations and explains why? (5 points)
(4, 14), because one of the lines passes through this point
(4, 14), because the point lies between the two axes
(5, 17), because both lines pass through this point
(5, 17), because the point does not lie on any axis
- = -2
9
What is the correct answer for this problem
Answer:
There are 200 girls in that school
Step-by-step explanation:
The correct and complete question is as folly;
In a school 3/5 pupils are boys. One day 1/6 of the boys were absent when 250 boys were present. How many girls are in the school?
SOLUTION
Let the total number of students in the school be x students
Since 3/5 are boys , then the number of girls in the school would be 1-3/5 = 2/5
The number of boys are 3/5 * x = 3x/5
The number of girls are 2/5 * x = 2x/5
Now on a particular day, 1/6 of the boys were absent and 250 boys were present.
What this means is that the fraction of boys present is 1-1/6 = 5/6
Now, 5/6 of the total boys population were present.
Mathematically;
5/6 * 3x/5 = 250
3x/6 = 250
x/2 = 250
x = 2 * 250 = 500
So there are 590 students in the school.
The number of girls in the school is ;
2x/5 = 2/5 * 500 = 200 girls
Answer:
Step-by-step explanation:
To find the slope of the line, we can look at the coefficient of x in the equation. In this case, the coefficient of x is 9/10. Therefore, the slope of the line is 9/10.