Sir Joseph John Thomson OM PRS was a British physicist and Nobel Laureate in Physics, credited with the discovery of the electron, the first subatomic particle to be discovered.
b. 1.52 molar solution
c. 11.2 molar solution
d. 87.2 molar solution
Answer:
a. 1.01 molar solution
Explanation:
Now we have to recall the formula;
n= CV
Where
n= number of moles of magnesium oxide
C= concentration of magnesium oxide solution = ???
V= volume of magnesium oxide solution= 365 ml
But;
n= m/M
Where;
m= given mass of magnesium oxide= 14.2 g
M= molar mass of magnesium oxide= 40.3044 g/mol
Substituting values;
14.2g/40.3044 g/mol = C×365/1000
0.3523= 0.365 C
C= 0.3523/0.365
C= 0.965
C= 1.00 molar (approx)
Answer:
Option A. 1.01 molar solution
Explanation:
Step 1:
Data obtained from the question. This include the following:
Mass of MgO = 14.92g
Volume of solution = 365mL
Molarity of solution =.?
Step 2:
Determination of the number of mole present in 14.92g of MgO.
This is illustrated below:
Mass of MgO = 14.92g
Molar mass of MgO = 24.3 + 16 = 40.3g/mol
Number of mole MgO =...?
Mole = Mass /Molar Mass
Number of mole of MgO = 14.92/40.3 = 0.370 mole
Step 3:
Determination of the molarity of the solution.
This can be obtained as follow:
Mole of MgO = 0.370 mole
Volume = 365mL = 365/1000 = 0.365L
Molarity =..?
Molarity = mole /Volume
Molarity = 0.370/0.365
Molarity = 1.01M
Answer: The molarity of solution is 1.39 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute =
= volume of solution in L
Now put all the given values in the formula of molality, we get
Therefore, the molarity of solution is 1.39 M