Can anyone help?? Please

Answers

Answer 1

Answer: 3O=12/3 Divide both sides by 3.
/3

O=4

♢+2=5(4)
♢+2=20
-2 -2 Subtract 2

♢=18

2(4)+18=2∆
8+18=2∆
26=2∆
/2 /2 Divide by 2

∆=13

Answer 2

Answer: The circle is worth 4 because it's being multiplied by 3. Then the diamond is 18 and the triangle is -5.

The measure of angle VSU is 35°.

Step-by-step explanation:

We know that the arc VST is 220°.

This means arc VUT is 140°, because it's the difference between the total arc 360° and 220°.

Also, we know that segments UV and UT are congruent, that means their arcs are also congruent. So, the measure of arc VUT can be equally divided, that means arc VU is 70°.

Now, the inscribed angle theorem states that the angle formed by two intersecting chords is half of its subtended arc.

$\angle VSU = (1)/(2) arc(VU)=(1)/(2)(70\°) \n \angle VSU = 35\°$

Therefore, the measure of angle VSU is 35°.

What is the equation of the line, in general form, that passes through the point (1, 1) and has a y-intercept of 2. possible answers: x - y + 2 = 0
x + y - 2 = 0
x - y - 2 = 0

Answers

To solve this problem we need to know the form of the general equation of the line. That is, y= mx+b where m is the slope and b is the intercept. We are already given the y-intercept (2) our next step is to fin the slope. Substitute the point give (1,1) in the equation y= mx+2 and then solve for m. The slope is then -6. The final equation is y = -x+2 or x + y - 2 = 0

the answer seems to be x+y-2=0

Somebody help please ASAP!

Answers

Answer: 4th box

Step-by-step explanation:

Find the angle measure that makes the statement true. Sin 25° = Cos ____ °

Answers

Since the sine and cosine functions are cofunctions, they are complementary. The format for this is that sinx=cos(90-x). This works for secant and cosecant and tangent and cotangent. So, sin25°=cos65°.

How do I solve x over 6 + 4+15 ?

Answers

x/6 + 4 = 15

First, subtract 4 to both sides:

x/6 = 11

Now multiply 6 to both sides:

x = 66

$x/6+4=15 \n x/10=15 \n *10\ \ \ *10 \n x=150$

PLEASE HELP!!!!!!!If JK = 6r, KL = 3r, and JL = 27, what is the value of r?

a. 1.5
b. 9
c. 3
d. 4

Answers

Well to solve for r, what you would need to do is make up an equation based on the expressions that represent the segments of the line in the image.

JK represents the first aspect of the line and is equal to 6r.

Likewise, KL represents the second component of the line and is equal to 3r.

We also know the total value from the first point to the last one, and that is 27.

Now simply add the first 2 expressions that represent the segments of the line and make it equal to the total length of the line, 27 and then solve for r.

6r + 3r = 27
9r = 27
r = 27/9
r = 3.

So now we know that JK is 6 • 3 = 18 and KL is 3 • 3 = 9, thus adding both together will give a value of 27, 18 + 9 = 27.

The solution is C.3

Answer:

Its 3

Step-by-step explanation:

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