sqrt(-49) / [ (7-2i) - (4+9i) ]
= 7i / (3 - 11i)
= 7i (3+11i) / [ (3 - 11i) (3 + 11i) ]
= (21 i - 77) / (9 + 121) = choice (d), (-77 + 21i) / 130
integers: 1. ? 2. ?
2. c = -3
integers: 1. ? 2. ?
3. c = 6
integers: 1. ? 2. ?
4. c = 12
integers: 1. ? 2. ?
I asked this question a couple of minutes ago and I feel like it isn't being understood completely so I edited the question to specify a little bit and posting it again. I am hoping you all understand it now and give me the best results. A huge thank you to all who attempts to answer!
Answer:
Look at explanation plz
Step-by-step explanation:
1) so we know that b cannot be anything lower than 0
So let’s substitute -7 in place of c:
x^2+bx-7
Factors of -7: 7,-1. -7,1
Only factor pair that Will not result in a negative or 0: 7,-1
Integers for B: 7,-1
Let’s do the same with number 2:
X^2+bx-3
Factors of -3: 3,-1. -3,1
Only factor pair that will not result in a negative or 0: 3,-1
Integers for B:3,-1
3) you know the drill:
6= 3,2 -3,-2. 6,1 -6,-1
Positive integers of 6: 3,2 or 6,1
Values for B: 3,2 OR 6,1 your choice
4) 12= 12,1. -1,-12. 4,3. -4,-3 6,2. -6,-2
Values for B: 12,1 or 4,3 or 6,2