Sarah found the mean of a set of numbers to be 205.09.how should she read this value out loud?

Answers

Answer 1

Answer: two hundred and 5, point zero nine or 0 9

Answer 2

Answer: Two hundred five and nine

Related Questions

Simplify.25/55xA.5/11xB.1/2xC.x/2D.5x/12
2/3 x 1/4 in simplest form
What is the value of x? 12-x=7
At summer camp the ratio of boys to girls is 7:1. 1. If there were 63 boys how many girls were there?
grace made 7 bouquets for the bridesmaids in a wedding. she put 3 roses, 4 tulips, and 2 lilies in each bouquet. how many flowers did she use in all.?

A certain color is made by blending red paint and blue paint in a 9:4 ratio. How many liters of each are needed to make 65 liters of this color?

Answers

you would need 6.9 liters

7k^2-16k+100=0 using completing the square ?

Answers

$7k^2-16k+100=0$

$7k^2-16k=-100$

Add a squared constant to both sides:

$7k^2-16k+c^2=c^2-100$

On the left, we wish to condense the quadratic into a squared binomial,

$(\sqrt7\,k-c)^2$

Expanding this gives

$7k^2-2c\sqrt7\,k+c^2$

which tells us

$-2c\sqrt7=-16\implies c=\frac8{\sqrt7}$

Then $c^2=\frac{64}7$ , and

$\left(\sqrt7\,k-\frac8{\sqrt7}\right)^2=\frac{64}7-100$

$\left(\sqrt7\,k-\frac8{\sqrt7}\right)^2=-\frac{636}7$

If you're looking for real-valued solutions, there are none, since the square root of a negative number doesn't exist... but if you're allowing complex-valued solutions, we can take the square root of both sides to get

$\sqrt7\,k-\frac8{\sqrt7}=\pm 2i\sqrt{\frac{259}7}$

Multiply both sides by $\sqrt 7$ to eliminate denominators, then solve for $k$ :

$7k-8=\pm 2i√(259)$

$7k=8\pm 2i√(259)$

$\boxed{k=\frac{8\pm2i√(259)}7}$

4) At the end of the summer, I decide to drain the swimming pool. I noticed that it drains faster when there is more water in the pool. That was interesting to me, so I decided to measure rate at which it drains. I found that it was draining at a rate of 3% every 5 minutes How many gallons are left in the pool after 50 minutes?

Answers

Final answer:

After 50 minutes, the pool has 73.74% of its initial water left, meaning it drained 26.26% of the initial water. To represent this remaining amount in gallons, it would be 0.7324 times the initial volume (in gallons).

Explanation:

To answer your question regarding the amount of water left after draining the pool for 50 minutes with a drain rate of 3% every five minutes, it is important to understand that the reduction occurs in a compound manner. This means each time we are dealing with 97% (100% - 3%) of the previous total.

So after 10 iterations (equaling to your 50 minutes since each iteration is 5 minutes long), we are left with (0.97)^10 = 73.74% of the initial total. That means 26.26% of the water has been drained.

In terms of gallons, if X represents the initial volume of water in the pool, then 0.7324 * X gallons remain after 50 minutes. Without knowing the initial volume of the pool, it is impossible to give a precise value in gallons.

Learn more about Compound Reduction here:

brainly.com/question/35909343

#SPJ12

B. If m2s= 115°, what is m2S'?

Answers

Answer:

if it stayed the same and just moved then it will still be 115 degrees, the only thing that is ever changing is the coordinates.

Step-by-step explanation:

Find the percent change of 40 to 72

Answers

If you would like to know what is the percent change of 40 to 72, you can calculate this using the following steps:

x% of 40 = 72
x% * 40 = 72
x/100 * 40 = 72 /*100/40
x = 72 * 100 / 40
x = 180%

180% - 100% = 80%

The correct result would be an 80% increase.

40 to 72 would be 80%

72 = r 90 Whats R in this equation

Answers

rmemeber you can do anything to an equaiton as longn as you do it to both sides
also x times 1/x=1 since x/x=1
also x times 1=x

72=r90
divide both sides by 90
72/90=r
0.8=r

r=0.8

Other Questions

Please help!!!!!!!!!!!!.

Pat listed all the numbers that have 15 as a multiple

How many solutions does the system of equations have? A. The system has exactly one solution. B. The system has no solution. C. The system has infinitely many solutions.

A fifth grade class painted pieces of cardboard for an art project. Each piece of cardboard had an area of 6.25 square inches. The students painted 200 pieces of cardboard each day.A. What is the total area of cardboard that they painted by the end of the 3rd day? 6.25x200=1250 1250 x3= 3750 B. At the end of the 3rd day students glued together all the pieces of the painted cardboard to form a large square mural and they cut the mural into 40 strips of equal sizes so they could move the mural. What is the area of each smaller strip of cardboard? Express the answer in decimal form.