What are the greatest Common factor of 28 and 32

Answers

Answer 1

Answer: The factors of 28: 1; 2; 4; 7; 14; 28
The factors of 32: 1; 2; 4; 8; 16; 32

GCF(28; 32) = 4

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What is the answer for 3{5[10+5(500-100)+399]}

Answers

Okay. Handle 500-100 first. That brings it to 3{5[10+5(400)+399]}. Next, Handle 5(400). That brings you to 3{5{10+2,000+399]}. Then handle all the addition. That leads to 3[5(2,409)]. Next, configure 5(2409). That leads to 3(12045). Then do that one which ends as 36,135 for a final answer.

Handle 500-100 first. That brings it to 3{5[10+5(400)+399]}. then Handle 5(400). That brings you to 3{5{10+2,000+399]}. next handle all the addition. That brings you to 3[5(2,409)]. Next, configure 5(2409). That gives you 3(12045). Then do that one which ends as 36,135 for a final answer.qx

Write (5+2yi)(4-3i)-(5-2yi)(4-3i) on a+bi form, where y is a real number

Answers

the answer is attached here

For a scavenger hunt, Chessa put one coin in each of10 small boxes. Four coins are quarters, 4 are dimes, and 2 are nickels.How could you simulate choosing one box at random? Would you use thesame simulation if you planned to put these coins in your pocket andchoose one? Explain your reasoning.

Answers

first things first, there is more chance to getting the quarters and dimes, and a lesser chance to getting the nickels.

now in the pockets different, and depending if the coins are the same.

hope this helped!!!

An airline allows each passenger 33 kilograms of luggage. Carl has to lower the weight of his suitcase by 25% to stay within the limit. How much did the suitcase originally weigh?

Answers

Answer:

44 kg.

Step-by-step explanation:

The weight limit of the luggage = 33 kg

Let the original weight of the suitcase = x kg

Now, it has been given that Carl has to lower the weight of his suitcase by 25% to stay within the limit.

It means that if we decrease the original weight of the suitcase by 25% then it should be equal to 33 kg.

Thus, we have the equation

$x-0.25x=33$

Solve the equation

$0.75x=33\n\nx=(33)/(0.75)\n\nx=44$

Therefore, the original weight of the suitcase was 44 kg.

1- 0.25= 0.75 (multiplier)

33÷0.75=44

The suitcase originally weighed 44kg

Hope this helps!

Approximately how many degrees are in the measure of an interior angle of a regular eight sided polygon?

Answers

135° I think 1080( what the angles add up to) 1080÷8=135°

Solve with quadratic formula 8x^2-9x-5=0

Answers

$8x^(2) - 9x - 5 = 0$

$x = \frac{-(-9) +/- \sqrt{(-9)^(2) - 4(8)(-5)}}{2(8)}$

$x = (9 +/- √(81 + 160))/(16)$

$x = (9 +/- √(241))/(16)$

$x = (9 +/- 15.524)/(16)$

$x = 0.5625 +/- 0.97025$
$x = 0.5625 + 0.97025$ $x = 0.5625 - 0.97025$
$x = 1.53275$ $x = -0.40775$

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