The French club is holding a car wash fundraiser. They are going to charge $20 per car, and expect between 30 and 100 cars. Identify the independent and dependent quantity in the situation, and find reasonable domain and range values.A: number of cars; money raised; 30 to 100 cars; $600 to $2000
B: money raised; number of cars; 30 to 100 cars; $600 to $2000
C: number of cars; money raised; $600 to $2000; 30 to 100 cars
D: money raised; number of cars; $600 to $2000; 30 to 100 cars

Answers

Answer 1
Answer: independent variable = number of cars with domain 30 to 100 cars
dependent variable = moner raised with range $600 to $2000

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If P(x,y) is the point on the unit circle defined by real number theta , then csc theta= _____.x/y
y/x
1/x
1/y

Answers

csc thta =r/ y=1 /sin theta
see attachment below

Answer:1/y

Step-by-step explanation:

What is the area of a triangle base 25 feet and height 8 feet

Answers

How you get your answer is by multiplying 25*8= 125 
Area= 25*8/2= 100
Area of triangle= base*height/2

Solve the following system of equations by graphing and select the correct answer below:2x + 6y = 20
3x _ 2y = 8


Answers:
x = 4, y = 2
x = 4, y = _2
x = _2, y = 4
x = 2, y = 4

Answers

the only answer is x = 4, y = 2, 
2(4) + 6(2) = 20
3(4) _ 2(2) = 8
the graph is so easy, please try!!

Answer:

Option A is correct.

x =4 , y = 2

Explanation:

Given the system of equation:

2x+6y = 20                   ......[1]

3x-2y = 8                       .....[2]

Multiply equation [2] by 3 both sides we get;

3 \cdot (3x-2y) = 3 \cdot 8

Using distributive property:a\cdot (b+c) = a\cdot b+ a\cdot c

9x - 6y = 24                     .....[3]

Add equation [1] and [3], to get eliminate y we get;

2x+6y+9x-6y= 20+24

Combine like terms we have;

11x = 44

Divide both sides by 11 we get;

x = 4

Substitute the value of x =4 in [1] we get;

2(4) + 6y = 20

8 + 6y = 20

Subtract 8 from both sides we have;

6y = 12

Divide both sides by 6 we have;

y = 2

Therefore, the values of x and y are; 4 and 2.


Rob has 40 coins, all dimes and quarters, worth $7.60. How many dimes and how many quarters does he have?

Answers

The required Rob has 16 dimes and 24 quarters as he has a total of 40 coins.

What are equation models?

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

Here,
Let x be the number of dimes that Rob has, and y be the number of quarters.

We know that he has a total of 40 coins, so,

x + y = 40 ( 1)

We also know that the value of all his coins is $7.60. The value of x dimes is 10x cents, and the value of y quarters is 25y cents. So,

10x + 25y = 760 ( 2)

Now we can solve for x and y. Let's start by solving equation 1 for one of the variables:

x + y = 40

y = 40 - x

Substitute this expression for y into equation 2:

10x + 25y = 760

10x + 25(40-x) = 760

10x + 1000 - 25x = 760

-15x = -240

x = 16

So Rob has 16 dimes. We can use equation 1 to find the number of quarters:

x + y = 40

16 + y = 40

y = 24

So Rob has 24 quarters.

Therefore, Rob has 16 dimes and 24 quarters.

Learn more about models here:
brainly.com/question/13567219
#SPJ2

24 quarters and 16 dimes because 24*25=600 and 16*10=160 add them 2gether will be 760=$7.60

Mrs. Quotient asked her students to simplify each of the expressions below. Which of the numbered choices represents the expressions which simplified to the same result? A 71 B 72 C 73

Answers

Answer:

A and B

Step-by-step explanation:

Mrs. Quotient asked her students to simplify each of the expressions below. Which of the numbered choices represents the expressions which simplified to the same result? A 126/2 B 23 × 3 C 3 × 21

When simplifying an algebraic expression, the following steps are needed to be taken.

Firstly, remove parenthesis by multiplying the constant with the term in the parenthesis or remove parenthesis using exponent rules for parenthesis in exponent form.

Secondly Combine terms by adding coefficients of terms with the same order and lastly sum all constant.

A) 126/2

Applying the division rule give:

126/2 = 63

B) 23 × 3

Applying multiplication rule gives:

23 × 3 = 69

C) 3 × 21

Applying multiplication rule gives:

3 × 21 = 63

Both the results of expression A and expression B are simplified to the same result

Sue bought ten items at an average price of $3.60. The cost of eight of the items totaled $30. If the other two items were the same price, what was the price she paid for each ?1) $15, 2) $7.50, 3) $6, 4) $3, 5) $1.50I guess the answer is $7.50.What is yr answer ???

Answers

4) $3
Total price of the 10 items= $3.6x10=$36
The cost of the other two items=$36-$30=$6
The cost of each of the two= $6/2(because they are the same price)
                                       =$3


The answer is 4.) $3 each

She bought 8 items at $30 so those cost $3.75 each

8*$3.75=$30 

then add $6 +30= $36

$36/10 = $3.60 for average cost of each item

so the other 2 items cost $3 each