Holly finds that (11m – 13n + 6mn) – (10m – 7n + 3mn) = m – 20n + 9mn. What error did Holly make? a)he only used the additive inverse of 10m when combining like terms. b)She added the polynomials instead of subtracting. c)She only used the additive inverses of –7n and 3mn when combining like terms. d) She did not combine all like terms.
Answers
Answer:
a) She only used the additive inverse of 10m when combining like terms.
Step-by-step explanation:
Given : Holly finds that
First we open the bracket by multiplying minus sign in it, we get
Combining like terms we get, we get
→ correct answer.
When we compare the correct answer to the answer given by Holly, the first term is same in both the answers,
Therefore, She only used the additive inverse of 10m when combining like terms.
Answer:
answer A
Step-by-step explanation:
Related Questions
Add and simplify 9/16 + 1/2= ?
A combination lock has 5 different numbers. If each number can only be used ONCE, how many different combinations are possible?
Can 39/121 be simplified and if so what is it??
Simplify 24pn/18p^2 please and thank you
rhombuses
squares
quadrilaterals
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Answers
The chance that each number will occur is 1/7.
What is Probability?
Probability refers to potential. A random event's occurrence is the subject of this area of mathematics.
The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events.
The degree to which something is likely to happen is basically what probability means.
We have,
The list of numbers generated is; 0, 1, 2, 3, 4, 5, 6,
There are 7 alternative outcomes, and each one has an equal chance of occurring. The likelihood or possibility that any number will occur is determined by;
= number of times the number occurs / 7
= 1/7
Thus, the chances are 1/7.
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there are 7 number possibilities ex 0,1,2,3,4,5,6
So the odds of randomly generating one number would be 1 in 7 possibilities.
1/7
write and solve an equation to find the value of x (show work)
What is the length of RS
What is the length of UV
Answers
Answer:
The length of RS is 22
The length of UV is 22
Step-by-step explanation:
6x-8. ---------- equation (i)
4x+2 ------------ equation (ii)
Now,
equating equation i and ii, we get
6x-8 = 4x+2
or, 6x-4x = 2+8
or, 2x = 10
or, x = 10/2
.°. x = 5
Then,
length of RS = 6x-8
= 6×5-8
= 30-8
= 22
Again
length of UV = 4x+2
= 4×5+2
= 20+2
= 22
Final answer:
The value of x is 5. The length of both RS and UV is 22.
Explanation:
In mathematics, when two lines or segments are said to be equal, it means you can set your two given equations equal to each other. In this case, you can equate RS to UV, which would give you the equation 6x - 8 = 4x + 2. To solve for x, you would start by moving the 4x from the right side of the equation over to the left by subtraction to get 2x - 8 = 2. Next, to isolate x, you would move the 8 over to the right side of the equation using addition, so the equation becomes 2x = 10. Finally, divide each side by 2 to get x = 5. To find the lengths of RS and UV, substitute x = 5 into the original equations, yielding RS = 6*5 - 8 = 22 and UV = 4*5 + 2 = 22.
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Answers
B. y = x – 6
C. y = x + 6
D. y = x
Answers
y = mx + b
slope(m) = 1
(2,16)...x = 2 and y = 16
now we sub and find b, the y int
16 = 1(2) + b
16 = 2 + b
16 - 2 = b
14 = b
so ur parallel equation is : y = x + 14
Answers
x | p(x) = -16x^2+32x
--------------------------
1 | p(1) = -16(1)^2 + 32(1) = 16
2 | p(2) = -16(2)^2 + 32(2) = 0
Having obtained the desired result at x = 2, this means that the model rocket has been in the air for 2 seconds.
Final answer:
The model rocket is in the air for 0 seconds according to the given equation, which implies an immediate impact upon launch.
Explanation:
In this mathematical scenario, the model rocket's height p(x) over time x (elapsed seconds) is given by the quadratic equation p(x) = 16x^2 + 32x. The total amount of time the rocket is in the air will be the point when the rocket returns to ground level. This occurs when p(x) = 0, which represents the rocket's height being zero feet above the ground.
We can find out when this occurs by solving the quadratic equation for x. We can rearrange the quadratic equation to 16x^2 + 32x = 0. Factoring out 16x gives us 16x(x + 2) = 0. Solving for x will give two potential solutions: x = 0 (the initial launch point) and x = -2. However, since time cannot be negative in this context, we discard the -2 and our answer is x=0 s, the total time the model rocket will be in the air after being launched is 0 seconds.
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