The base of a cube is parallel to the horizon. A plane cuts through the cube creating a pentagon-shaped cross section. Which kind of plane could it be? A. a vertical plane cutting two adjacent edges of the base B. a vertical plane cutting two opposite edges of the base
C. a slanting plane cutting two adjacent edges of the base
D. a slanting plane containing exactly one edge of the cube

Answers

Answer 1

Answer: I think the answer is C. a slanting plane cutting two adjacent edges of the base. I thought of the Pentagon building in Washington where it also has a pentagon-shaped cross section.

Answer 2

Answer:

Answer:

C. a slanting plane cutting two adjacent edges of the base

Step-by-step explanation:

The base of a cube is parallel to the horizon. A plane cuts through the cube creating a pentagon-shaped cross section. The plane could be - a slanting plane cutting two adjacent edges of the base.

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What is 15/8 as a mixed number

When a bill is not paid by the due date, a late fee is added each month until the bill is paid. The values in the table represent the total amount due, in dollars, for each month that a payment remains overdue.Months | Total due
2 300
5 375
10 500
Using x for the number of months overdue and y for the total amount due, in dollars, construct a linear function that describes the relationship between the number of months the bill is overdue and the total amount due. Enter the equation of the function in the box

Answers

The total amount due, in dollars, is an illustration of a linear function

The equation of the function is $y = 25x + 250$

Represent the month with x, and the total due with y.

Start by calculating the slope (m) using:

$m = (y_2 -y_1)/(x_2 -x_1)$

So, we have:

$m = (375 - 300)/(5 - 2)$

Simplify

$m = (75)/(3)$

Divide 75 by 3

$m = 25$

The linear equation is then calculated as:

$y = m(x - x_1) + y_1$

So, we have:

$y = 25(x - 2) + 300$

Open bracket

$y = 25x - 50 + 300$

Add 300 to -50

$y = 25x + 250$

Hence, the equation of the function is $y = 25x + 250$

Read more about linear equations at:

brainly.com/question/4074386

Sparkle is 464 mm long and twilight is 46 cm long which of Amelia's cats is longer

Answers

If Sparkle is 464 mm long and twilight is 46 cm long then Sparkle is longer than Twilight by 4 mm.

What is Unit of Measurement?

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

To compare the length of Sparkle and Twilight, we need to convert their lengths to the same unit of measurement.

Sparkle's length is given in millimeters (mm), while Twilight's length is given in centimeters (cm).

To convert Twilight's length to millimeters, we can multiply by 10

1 centimeter = 10 milli meters

Twilight's length in millimeters

= 46x 10

= 460 mm

Now we can compare the lengths:

Sparkle: 464 mm

Twilight: 460 mm

Therefore, Sparkle is longer than Twilight by 4 mm.

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#SPJ2

464 mm is longer because it is 46.4 cm and twilight is 46 cm. Change mm to cm by moving the decimal point of the mm back one point.

24,25,26 is a pythagorean triplet. True or fals

Answers

Step-by-step explanation:

for this the Pythagoras equation must be true :

c² = a² + b²

c is the Hypotenuse the dude opposite of the right angle in a right-angled triangle.

as such it had to be the longest side.

so, c = 26

and we get

26² = 24² + 25²

676 = 576 + 625 = 1201

wrong, 1201 is not equal to 676, so, 24, 25, 26 are NOT a pythagorean triplet.

theinitialstatementisfalse.

I need help on this question please help?

Answers

a) $(7)/(20)$
b) $(2+7)/(20)=(9)/(20)$
c) $0$

Hello !

a) $7/20$

b) $2/20 + 7/20 \n=(2+7)/20 \n =9/20$

c) $The answer is 0.$

What should be added to 3 to make the sum 0?

−3
−2
0
3

Answers

The answer is (-3) because if you have 3, you need to take away three in order to get to 0

Answer:

the answer is 3

Step-by-step explanation:

Additive inverses:

pairs of numbers that have a sum of zero.

Find the x-intercept of the parabola with vertex (6,27) and y-intercept (0,-81)

Answers

The vertex form of the equation of a parabola with the vertex (h,k):
$y=a(x-h)^2+k$

The parabola has the vertex at (6,27).
$y=a(x-6)^2+27$

The y-intercept is (0,-81).
$x=0, \ y=-81 \n\Downarrow \n-81=a(0-6)^2+27 \n-81=a(-6)^2+27 \n-81=36a+27 \n-81-27=36a \n-108=36a \n(-108)/(36)=a \na=-3$

The equation of the parabola is:
$y=-3(x-6)^2+27$

y=0 at the x-intercepts.
$0=-3(x-6)^2+27 \n-27=-3(x-6)^2 \n(-27)/(-3)=(x-6)^2 \n9=(x-6)^2 \n√(9)=√((x-6)^2) \n3=|x-6| \nx-6=3 \ \lor \ x-6=-3 \nx=3+6 \ \lor \ x=-3+6 \nx=9 \ \lor \ x=3$

The x-intercepts are x=3 and x=9.

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