Cameron opens a checking account and a savings account at his local bank. He deposits $10,000 into his checking account and $2,000 into his savings account. He will withdraw $1,200 from his checking account each year. His savings account earns 8% interest each year. In how many years will both accounts have the same balance?

Answers

Answer 1
Answer: The correct answer is:
5.9 years.

Explanation:
 Let x be the number of years. For the checking account, our expression would be 10000-1200x, since he withdraws $1200 from his account each year, and he begins with $10,000.

The formula for simple interest is:
I=prt
where:
p is the principal, r is the rate and t is the time

using our information, we have
p=2000,
r=8%=8/100=0.08, and
t=x.

This gives us 2000(0.08)(x).
However, we must add the $2000 to this (interest is added on to the principal); this gives us:
2000+2000(0.08)(x).

Setting these two equal, we have:
10000-1200x = 2000+2000(0.08)(x).

Simplifying the right hand side, we have:
10000-1200x=2000+160x.

Add 1200x to both sides:
10000-1200x+1200x=2000+160x+2000x;
10000=2000+1360x.

Subtract 2000 from both sides:
10000-2000=2000+1360x-2000;
8000=1360x.

Divide both sides by 1360:
(8000)/(1360) = (1360x)/(1360);
5.9=x.
Answer 2
Answer:

Let x be the number of needed years.

1. He deposits $10,000 into his checking account and he will withdraw $1,200 from his checking account each year. Then after x years he will have $10,000-$1,200x in his checking account.

2.  He deposits $2,000 into his savings account and his savings account earns 8% interest each year, then after x years he will have \$2,000\cdot (1.08)^x.

3. Equate these amounts of money:

10,000-1,200x=2,000\cdot (1.08)^x.

4. Solve this equation:

  • divide the equation by 400:

25-3x=5\cdot (1.08)^x;

  • plot graphs of the function y=25-3x and y=5\cdot (1.08)^x (see attached diagram);
  • find the common point of these two graphs: (6.663,5.01).

Conclusion: he needs nearly 6.663 years.


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Step-by-step explanation:

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Answers

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Answers

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= (2a)² - 5²

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What is the slope of a line perpendicular to x - 5y = -10?What is the slope of a line parallel to 4x + y = -1?

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Answers

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-5y = -x - 10
y = 1/5x + 2.....slope here is 1/5...perpendicular line needs a negative reciprocal slope. All that means is flip the slope and change the sign.
1/5......flip.....5/1.....change the sign....-5/1...or just -5 <== answer

 slope of line parallel to 4x + y = -1
y = -4x - 1...slope here is -4....parallel lines will have the same slope
answer is : -4

slope of line perpendicular to x - 3y = 9
-3y = -x + 9
y = 1/3x - 3....slope = 1/3.....flip...3/1....change sign...-3 <== answer

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y = 2x - 8/5....slope = 2....parallel lines have same slope...answer = 2

slope of line parallel to 4x + 2y = 5
2y = -4x + 5
y = -2x + 5/2.....slope = -2


y=-4x would be parallel to 4x + y = -1

y=-3x would be perpendicular to x - 3y = 9

y=-2x would be parallel to 10x - 5y = 8

y=2x would be parallel to 4x + 2y = 5