What is the unit rate of the ingredients in your recipe?

Answers

Answer 1
Answer: Unit rate just means whatever measurement per ONE unit. If you were baking a batch of 12 cookies and you needed one cup. The unit rate would be 1/12cup of flour per ONE cookie

Answer 2
Answer:

The unit rate is the amount of each ingredient needed for a single piece of the recipe's output. You can find it by dividing the total amount of an ingredient by the total quantity of the food being made.

The unit rate in a recipe refers to the amount of each ingredient required per single unit of the desired output. For example, if a recipe requires 2 cups of flour to make 4 cookies, the unit rate of flour would be 0.5 cup per cookie. To find the unit rate, divide the total amount of an ingredient by the total number of units produced. So in this case, 2 cups ÷ 4 cookies = 0.5 cup/cookie. This means you need half a cup of flour for each cookie you want to make.

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One third of the opposite of a number is less than 12

Answers

The number would be greater then 36.

What is inequality?

An inequality is a relation which makes a non-equal comparison between two numbers or mathematical expressions.

here, we have,

Let x represent the unknown number.  The opposite of this number would be represented by -x.

1/3 of this is found by multiplying by 1/3; this gives us

1/3×(-x)

Since it is less than 12, this gives us

1/3×(-x) < 12

To cancel the 1/3, we can multiply both sides by 3:

1/3×(-x)×(3) < 12×(3)

-x < 36

We can cancel the negative by dividing both sides by -1.  When we multiply or divide an inequality by a negative number we flip the inequality:

-x/-1 < 36/-1

x > 36

Our number must be greater than 36.

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Answer:

The number would be greater then 36.

Step-by-step explanation:

Let x represent the unknown number.  The opposite of this number would be represented by -x.

1/3 of this is found by multiplying by 1/3; this gives us

1/3(-x)

Since it is less than 12, this gives us

1/3(-x) < 12

To cancel the 1/3, we can multiply both sides by 3:

1/3(-x)(3) < 12(3)

-x < 36

We can cancel the negative by dividing both sides by -1.  When we multiply or divide an inequality by a negative number we flip the inequality:

-x/-1 < 36/-1

x > 36

Our number must be greater than 36.

1 & 2) what are the surface areas? please explain.

Answers

To find the surface area of a cylinder, use the formula SA = 2(pi)(radius^2) + 2(pi)(radius)(height).

So now, plug in what you know.

SA = 2(3.14)(5^2) + 2(3.14)(5)(9)
SA = (6.28)(25) + (6.28)(45)
SA = 157 + 282.6
SA = 439.6 square cm

439.6 square cm is your surface area
To find the surface area of a cylinder, use the formula SA = 2(pi)(radius^2) + 2(pi)(radius)(height).

So now, plug in what you know.

SA = 2(3.14)(5^2) + 2(3.14)(5)(9)
SA = (6.28)(25) + (6.28)(45)
SA = 157 + 282.6
SA = 439.6 square cm

439.6 square cm is your surface area

Hope this helps.

What does the mode of this set of data represent?

Answers

It should be D because the mode is the value that occurs the most often. 

PLEase help I really need this

Answers

Answer:

54 - 8 = $46

Step-by-step explanation:

ok the answer is 46 dollars

3/14 - 1/7= how much

Answers

3/14 - 1/7 
= 3/14 - 2/14
= 1/14

so, 3/14 - 1/7 = 1/14
1/14 is the answer, you have to find a common denominator which in this case is 14. and then you subtract both of the fractions like normal.

Help please! this is due tomorrow so please help out! will mark as brainiest!!

Answers

Answer:

\large\boxed{\bold{Q1}\ -(128)/(9)}\n\boxed{\bold{Q2}\ 2^(25)}

Step-by-step explanation:

\bold{Q1}\n\n(-2(3^2\cdot3^3)^2)/(3^(12)\cdot2^(-6))\qquad\text{use}\ a^n\cdot a^m=a^(n+m)\n\n=-(2(3^(2+3))^2)/(3^(12)\cdot2^(-6))=-(2(3^5)^2)/(3^(12)\cdot2^(-6))\qquad\text{use}\ (a^n)^m=a^(nm)\n\n=-(2\cdot3^(5\cdot2))/(3^(12)\cdot2^(-6))=-(2\cdot3^(10))/(3^(12)\cdot2^(-6))\qquad\text{use}\ (a^n)/(a^m)=a^(n-m)\n\n=-2^(1-(-6))\cdot3^(10-12)=-2^(7)\cdot3^(-2)\qquad\text{use}\ a^(-n)=(1)/(a^n)\n\n=-2^7\cdot(1)/(3^2)=-(2^7)/(3^2)=-(128)/(9)

\bold{Q2}\n\n(4^2)/(4^(-7))\cdot(2^4\cdot2^3)\cdot(3^(-2))^0\qquad\text{use}\ (a^n)/(a^m)=a^(n-m),\ a^n\cdot a^m=a^(n+m),\ a^0=1\n\n=4^(2-(-7))\cdot2^(4+3)\cdot1=4^(9)\cdot2^7=(2^2)^(9)\cdot2^7\qquad\text{use}\ (a^n)^m=a^(nm)\n\n=2^(2\cdot9)\cdot2^7=2^(18)\cdot2^7\qquad\text{use}\ a^n\cdot a^m=a^(n+m)\n\n=2^(18+7)=2^(25)