3 days to 1 week. Type as a ratio in the form of a fraction

Answers

Answer 1

Answer: 3 days : 1 week

1 week = 7 days

therefore 3 days : 1 week = 3 days : 7 days = 3 : 7

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What is the simplified square root of 1/56?

Answers

$\sqrt { \frac { 1 }{ 56 } } \n \n =\frac { \sqrt { 1 } }{ \sqrt { 56 } } \n \n =\frac { 1 }{ \sqrt { 7\cdot 8 } } \n \n =\frac { 1 }{ \sqrt { 7\cdot 2\cdot 4 } }$

$\n \n =\frac { 1 }{ \sqrt { 14\cdot 4 } } \n \n =\frac { 1 }{ \sqrt { 14 } \sqrt { 4 } } \n \n =\frac { 1 }{ 2\cdot \sqrt { 14 } } \n \n =\frac { 1 }{ 2\cdot \sqrt { 14 } } \cdot \frac { \sqrt { 14 } }{ \sqrt { 14 } } \n \n =\frac { \sqrt { 14 } }{ 2\cdot 14 } \n \n =\frac { \sqrt { 14 } }{ 28 }$

15 donuts in 3 boxes = how many donuts per box

Answers

Answer:

Step-by-step explanation:

divide

Does 2/3x+3/4=8 and 8x=87 have the same solution ?

Answers

(2/3)x + (3/4) = 8
-(3/4) -(3/4)

(2/3)x = 7.25(3/2)
(3/2)

x = 10.875

8x = 87 Divide both sides by 8

x = 10.875

So yes both sides have the same solution

Hope this helps :)

yes it does as far as i can see

The elements of a function of x are (-4,1), (-2,0), (8,-1). What is the domain of the function?

Answers

Domain is the first value or xs

[-4, -2, 8]

Which sentence fully illustrates that polygon ABCD is congruent to polygon PQRS?

Answers

Ans: Polygon ABCD maps to polygon PQRS through a reflection only.

Explanation:
As you can see in the figure that the polygon PQRS is the reflection of the polygon ABCD. If we reflect the polygon ABCD on the x-axis, we would get the polygon PQRS. Congruency means that both shapes have the same measure, which in this case, both these shapes have the same measure. Therefore, we can say that polygon ABCD maps to polygon PQRS through a reflection only in order to be congruent to each other.

Answer:

polygon ABCD maps to polygon PQRS through a reflection only.

Step-by-step explanation:

From 12 prepared songs, a bandchooses 3 to perform on a TV show. One
song will be played at the beginning of
the show, one in the middle, and one at
the end. Tell how many different set lists
are possible. Then tell if the situation
involves permutations or combinations.