What is the greatest common factor
15abc^2 and 25a^3bc

Answers

Answer 1

Answer: To find the greatest common factor, first find the largest evenly divisible number that you can take out in both numbers, in this case 15 and 25. Then find the greatest or highest number of each variable that you can evenly take out or divide in both terms, this is for a, b and c.

So GCF of 15 and 25 would be 5
GCF of a = a^1 or a
GCF of b = b^1 or b
GCF of c = c^1 or c
Put everything together to find the GCF.
GCF = 5abc.

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Plz Help. Will give braniest if answered correctly with an explanation!!!

Solve the value of x in the following proportion 6:9=x:72

Answers

So first find out: How much larger or smaller is the second proportion compared to first?
72 is 8 times bigger than 9, so the second proportion must be 8 TIMES BIGGER
Now, multiply 6*8=x
48=x
So in the end, x is 48.

How would you solve the following geometry problem?:∆PQR, find the measure of ∡P.

In Triangle PQR where angle Q is a right angle. QR measures 33 point 8; PQ measures 57 point 6; measure of angle P is unknown.

Answers:
30.4°

35.9°

54.1°

59.6°

What I did:
equation: tan(x) = 33.8/57.6
tan(x)=0.56
But I know that isn't correct.

Answers

What you did is correct. However the one you get is the tangent value of x. you have to find out the tan inverse of that value to find out the actual degree.

tan(x) = 33.8 / 57.6
tan(x) = 0.587
x = tan^-1 (0.587)
x = 30.4 degrees

A ladder of length 2x+1 feet is positioned against a wall such that bottom is x-1 feet away from a wall. The distance between the floor and top of the ladder is 2x. Assume that a right angle is formed by wall and the floor.

Answers

so leangh of ladder=2x+1

bottom edgre=x-1
wall edge=2x

so therefor, since this is a right triangle, use pythagorean theorem
a^2+b^2=c^2
c=hypotonues=longest side
b and a=sides touching the right angle

so x-1 and 2x are a and b
2x+1=c

subsitute
(x-1)^2+(2x)^2=(2x+1)^2
x^2-2x+1+4x^2=4x^2+4x+1
add like terms
5x^2-2x+1=4x^2+4x+1
subtract 1 from both sdies
5x^2-2x=4x^2+4x
subtract 4x from both sdies
5x^2-6x=4x^2
subtract 4x^2 from both sides
x^2-6x =0
factor out the x using distributive property which is
ab+ac=a(b+c)
x^2-6x=x(x-6)
(x)(x-6)=0

if xy=0 then assume x and/or y=0
x=0
we remember that one of the side legnths is 2x and if x=0 then the side legnth=0 which is not possible, so we discard

x-6=0
add 6 to both sides
x=6

subsitute and solve

legnth of ladder=2x+1
x=6 subsitute
2(6)+1=12+1=13
legnth of ladder =13 feet

height=2x
2(6)=12
height=12 feet

base=x-1
6-1=5

legnth of ladder=13 feet
height=12 feet
base=5 feet

pythagorean theorem
c^2 = a^2 + b^2

c = 2x+1
a = 2x
b = x-1

plug in and get:
(2x+1)^2 = (2x)^2 + (x-1)^2
4x^2 + 4x + 1 = 4x^2 + x^2 - 2x + 1 [distributed]
4x^2 + 4x + 1 = 5x^2 - 2x + 1 [added like terms]
x^2 - 6x = 0 [subtracted 4x^2 and 4x and 1]
x(x-6)=0 [factored out x]
x can equal 0 or 6

0 would not make any sense physically
therefore x = 6
plug this back into the length of the ladder 2x+1
2(6)+1 = 12 + 1 = 13

therefore the ladder is 13 feet long

Which Matrix is equal to the product Hj? Picture attached below! Will award brainliest also will report incorrect answer!

Answers

Hello,

(2,3)*(3,1)=(2,1) (range)
Answer
(0 )
(68)

Find the quadratic function y = a(x-h)^2whose graph passes through the given points (6, -1) and (4, 0). a) y = 1/4(x-5)^2 b) y = 1/4(x-5)^2 c) y = -1/4(x-6)^2 d) y = 1/4(x-6)^2

Answers

Answer: -1/2x - 2.

Step-by-step explanation:

To find the quadratic function y = a(x-h) that passes through the points (6, -1) and (4, 0), we can substitute the given points into the equation and solve for a and h. Let's go through the steps:

1. Substitute the coordinates of the first point (6, -1) into the equation:

-1 = a(6 - h)

2. Substitute the coordinates of the second point (4, 0) into the equation:

0 = a(4 - h)

3. Now we have a system of two equations with two unknowns. We can solve this system to find the values of a and h.

From the equation -1 = a(6 - h), we can rewrite it as:

-a(6 - h) = 1

From the equation 0 = a(4 - h), we can rewrite it as:

-a(4 - h) = 0

4. Simplifying the equations, we get:

-6a + ah = 1 (equation 1)

-4a + ah = 0 (equation 2)

5. Subtracting equation 2 from equation 1 eliminates the ah term:

-6a + ah - (-4a + ah) = 1 - 0

-6a + ah + 4a - ah = 1

-2a = 1

6. Solving for a, we divide both sides by -2:

a = -1/2

7. Substitute the value of a back into either equation (let's use equation 2) to solve for h:

-4(-1/2) + h(-1/2) = 0

2 + h/2 = 0

h/2 = -2

h = -4

8. Now we have the values of a = -1/2 and h = -4. We can substitute these values back into the original equation y = a(x-h) to find the quadratic function:

y = -1/2(x - (-4))

y = -1/2(x + 4)

y = -1/2x - 2

Therefore, the quadratic function that passes through the points (6, -1) and (4, 0) is

AI-generated answer

To find the quadratic function y = a(x-h) that passes through the points (6, -1) and (4, 0), we can substitute the given points into the equation and solve for a and h. Let's go through the steps:

1. Substitute the coordinates of the first point (6, -1) into the equation:

-1 = a(6 - h)

2. Substitute the coordinates of the second point (4, 0) into the equation:

0 = a(4 - h)

3. Now we have a system of two equations with two unknowns. We can solve this system to find the values of a and h.

From the equation -1 = a(6 - h), we can rewrite it as:

-a(6 - h) = 1

From the equation 0 = a(4 - h), we can rewrite it as:

-a(4 - h) = 0

4. Simplifying the equations, we get:

-6a + ah = 1 (equation 1)

-4a + ah = 0 (equation 2)

5. Subtracting equation 2 from equation 1 eliminates the ah term:

-6a + ah - (-4a + ah) = 1 - 0

-6a + ah + 4a - ah = 1

-2a = 1

6. Solving for a, we divide both sides by -2:

a = -1/2

7. Substitute the value of a back into either equation (let's use equation 2) to solve for h:

-4(-1/2) + h(-1/2) = 0

2 + h/2 = 0

h/2 = -2

h = -4

8. Now we have the values of a = -1/2 and h = -4. We can substitute these values back into the original equation y = a(x-h) to find the quadratic function:

y = -1/2(x - (-4))

y = -1/2(x + 4)

y = -1/2x - 2

Therefore, the quadratic function that passes through the points (6, -1) and (4, 0) is y = -1/2x - 2.

What is three hundred and twenty six to the nearest ten