There are 39 donuts in 3 boxes. Calculate the unit rate of donuts per box. *

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

All you do is divide 39 by 3 and that gets 13

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Evaluate: 20/ 5·2^-3

Answers

2^-3 = 0.125
0.125 x 5 = 0.625
20/0.625 = 32

The answer is 32.

Step-by-step explanation:

$= (20)/(5) . {2}^( - 3)$

$= 4. \frac{1}{ {2}^(3) }$

$= (4)/(2 * 2 * 2)$

$= (4)/(8)$

$= (1)/(2)$

Write 2/3 and 3/4 as a pair of fractions with a common denominator

Answers

in short simply we "multiply one fraction's top and bottom by the other's denominator", so let's do so,

$\bf \cfrac{2\cdot 4}{3\cdot 4}\implies \boxed{\cfrac{8}{12}}\qquad \qquad \qquad \qquad \qquad \cfrac{3\cdot 3}{4\cdot 3}\implies \boxed{\cfrac{9}{12}}$

3. Length of a cubic container is 20 cm .A cube with a length of edges 5 cm will be used to take some water from a water barrel. Determine the maximum number of cubes that need to use to fill the container with water.

Answers

We have l = 20 * 20 * 20 = 8000 cm3

One cube will have l = 5 * 5 * 5 = 125 cm3

-> The maximum number of cubes that need to use to fill the container with water is 8000 / 125 = 64

Find three consecutive ODD integers such that the sum of 7 times the smallest and twice the largest is -91. Name the smallest integer..

Answers

Answer:

-11, -9, -7

the smallest: 2x+1 = -11

Step-by-step explanation:

{z - some integer}

2z+1 - the smallest number

7(2z+1) - seven times the smallest number

2z+1+2=2z+3 - the middle number

2z+3+2 = 2z+5 - the largest number

2(2z+5) - twice the largest number

7(2z+1) + 2(2z+5) - the sum of 7 times the smallest and twice the largest

7(2z+1) + 2(2z+5) = -91

14z + 7 + 4z + 10 = -91

-17 -17

18z = -108

÷18 ÷18

z = -6

2z+1 = 2(-6)+1 = -12 + 1 = -11

2z+3 = 2(-6)+3 = -12 + 3 = -9

2z+5 = 2(-6)+5 = -12 + 5 = -7

Final answer:

To solve this problem, we denote the smallest odd integer as 'x' and set up the equation 7x + 2(x+4) = -91. By solving this equation, we find that the smallest integer is -15.

Explanation:

To find the three consecutive odd integers, let us denote the smallest odd integer as x; therefore, the next two consecutive odd integers would be x + 2 and x + 4, respectively. The problem states that the sum of seven times the smallest integer and twice the largest integer equals to -91. So, we can translate this into the equation, 7x + 2(x+4) = -91. Solving this gives us x = -15. Hence the smallest integer is -15. The full solution is as follows: