Rational and irrational numbers

Answers

Answer 1
Answer: A rational number is any number that can be rewritten as a fraction with both numerator and denominator are whole numbers.
Such an example is 5/1

An irrational number, on the other side, is a real number which cannot be written as a ratio of integers.

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What two numbers add to 10 and multiply to -192? How do you find it?I know I already asked this but I wasn't able to find the numbers. Please help me.
Subtract. Write your answer in simplest form. 4 5/8 - 1 1/8=____
F(x) = x, g(x) = 2xcombining functions

rich wrote this expression to describe the total distance he was going to bike in two days. Which situation could be described by this expression? A. Rich wasn't sure how far he would bike on the first day. He would bike 7 fewer miles on the second day. B. Rich wasn't sure how far he would bike on the first day. He would bike 7 miles the second day. C. Rich wasn't sure how far he would bike on the first day. He would bike 7 times farther the second day. D. Rich wasn't sure how far he would bike on the first day. He would bike the same distance for 7 days.plz hurry thx

Answers

B.  Rich wasn't sure how far he would bike on the first day. He would bike 7 miles the second day.
The first day is b and the second day is 7 miles.

Find the areaRenata is completing a craft project that involves covering only the lateral surface of a cylindrical container with fabric. The cylinder has a height of 12.8 in. and a radius of 15.1 in. To the nearest square unit, how much fabric does she need for this project? Use a calculator.

Answers

Answer: Renata needs 1,214 square inches fabric for this project.

Data:
Height of the cylinder: h=12.8 in
Radius of the cylinder: r=15.1 in
Lateral surface of the cylinder: S=?

Solution:
S=2 Pi r h; Pi=3.1416

Replacing the known values:
S=2 (3.1416) (15.1 in) (12.8 in)
S=1,214.416896 in^2
S=1,214 in^2

Is 4 kilograms is egual to 4000mgs

Answers

No.
So, there are 1000 milligrams in one gram, making the 4000 mgs equal to 4 grams.
There are 1000 grams in one kilogram, so 4 kilograms is equal to 4000 grams.

4000 =/= 4
So, 4 kilograms and 4000 milligrams are not equal.
4000Mgs is not equal to 4 kilograms. 4000 Mgs is 4 grams, which is 0.004Kilograms. Hence, 1 milogram is 1x10^-6 Kilograms.

How do you find the exact area of a circle having the given circumference of 3 pi

Answers

3.14 times the square of ur radius is equal to area of a circle. So in this case , they having the given circumference of 3pi , then u divided by 2 is ur radius. Radius is 1.5. 3.14 times 1.5 square or 3.24 times 1.5 times 1.5 it will get ur final answer. ( I don't have my calculator with me so I gave u a direction only )

Hi, I need help with this math question .
The image posted below

Answers

(6, 8). Substitute the numbers in for x and y and then solve the equation. The coordinates are (x, y).

Answer:

(6,8)

Step-by-step explanation:

\n \sf\longmapsto y=(1)/(3)x+2

  • Put the value

\n \sf\longmapsto 8=(1)/(3)(6)+2

\n \sf\longmapsto 8=2+2

\n \sf\longmapsto 8\neq 4

Liquid A has a density of 0.7g/cm^3liquid B has a density of 1.6g/cm^3

140g of liquid A is and 128g of liquid B are mixed to make liquid C

work out the density of liquid C

Answers

density is defined as mass per unit volume

in this case liquids A and B with 2 different densities are mixed and we are asked to find the density of the liquid C


liquid A has a density of 0.7 g/cm³

mass of liquid A added is 140 g

therefore volume of liquid A added is - 140 g / 0.7 g/cm³ = 200 cm³


liquid B has a density of 1.6 g/cm³

mass of liquid B added is 128 g

volume of liquid B added is - 128 g / 1.6 g/cm³ = 80 cm³


the total mass of liquid C after adding liquid A and B = 140 g + 128 g = 268 g

total volume in liquid C - 200 cm³ + 80 cm³ = 280 cm³

density of liquid C = mass / volume

= 268 g / 280 cm³ = 0.957 g/cm³

density of liquid C - 0.957 g/cm³

\rho = (m)/(V) \Rightarrow V=(m)/(\rho)
ρ - density, m - mass, V - volume

Liquid A:
\rho=0.7 \ (g)/(cm^3) \nm=140 \ g \n\n V=(140 \ g)/(0.7 \ (g)/(cm^3))=200 \ cm^3

Liquid B:
\rho=1.6 \ (g)/(cm^3) \nm=128 \ g \n\n V=(128 \ g)/(1.6 \ (g)/(cm^3))=80 \ cm^3

Liquid C:
m=140 \ g + 128 \ g=268 \ g \nV=200 \ cm^3 + 80 \ cm^3=280 \ cm^3 \n \n\rho=(268 \ g)/(280 \ cm^3) \approx 0.96 \ (g)/(cm^3)

The density of liquid C is approximately 0.96 g/cm³.