The diameter of the circle would be a line going through the center of the circle connecting to both sides.
The radius of a circle would be a line only going to the the center, or in other words, half the circle.
I hope this makes sense!
- STEP 4: LOOK BACK
According to soap box derby rules, a racer must weigh 250
pounds or less. The Math Club's car weighed in at 266
pounds on the day of the derby. How many pounds did the
Math Club need to remove from their soap box racer?
Dana added the weight limit to the Hector subtracted the weight limit
racer's weight. Since
from the racer's weight. Since
250 +266 = 516, the Math Club 266 - 250 = 16, the Math Club
needed to remove 516 pounds from needed to remove 16 pounds
the racer
from the racer
O A. Dana
B. Hector
b is the awnser
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
There are 96 squares in total. Yard is 3 feet, so you would divide the total by 3.
Answer:
I belive it would be 1/5. ;;;
Solve for t: 5t - 4 = 11
Answer:
t=3
Step-by-step explanation:
5t-4=|11
+4 |+4
5t= | 15
÷5 | ÷5
t = 3
Answer:
X × $75000 = $75000
Step-by-step explanation:
Brainliest would be appreciated
Answer: 373.22 feet
Step-by-step explanation:
The attached photo contains the diagram illustrating the scenario. 2 right angle triangles ACD and BCD are formed.
The distance between the two posts is AD + BD
To determine AD, we would apply the tangent trigonometric ratio which is expressed as
Tan θ = opposite side/adjacent side
Tan 46 = 200/AD
AD = 200/Tan 46 = 200/1.0355
AD = 193.14
To determine BD, we would also apply the tangent trigonometric ratio. Therefore
Tan 48 = 200/BD
BD = 200/Tan 48 = 200/1.1106
BD = 180.08
Therefore, the distance between the two posts is
193.14 + 180.08 = 373.22 feet