Answer:
8 students.
Step-by-step explanation:
We have been given that there are 24 sixth graders and 40 7th graders. We are asked to find the greatest possible number of students in each group having equal size.
To solve our given problem, we will find greatest common factor of 24 and 40.
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24.
Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40.
We can see that greatest common factor of 24 and 40 is 8, therefore, there would be 8 students in each group.
Answer:
c. 8×4-(2×3+8)÷2
Step-by-step explanation:
Using the rules of BODMAS,
B stands for bracket
O stands for Order
D stands for Division
M stands for Multiplication
A stands for Addition
S stands for Subtraction
8×4-(2×3+8)÷2
Now using this rule we will first of all open the bracket, In the bracket we multiply then add
8 × 4 - (6 +8) ÷ 2
8 × 4 - 14 ÷ 2
Still applying the rule, we divide 14 by 2 to give us 7
8 × 4 - 7
Then, still applying the rule, we multiply 8 by 4 which will give us 32
32 - 7
Then we finally subtract 7 from 32 to give us 25
32 - 7 = 25
So the expression; 8×4-(2×3+8)÷2 is equivalent to 25
Answer:
(4/9)x - 10 > (1/3)x - 12
4x - 90 > 3x - 108
x > -18