To determine the total number of People in the library, we can use the given ratio of adults to children. By setting up an equation and solving for the number of adults, we find that there are 25 adults. Adding this to the number of children gives us a total of 127 people in the library.
To find out how many people are there in the library altogether, we need to determine the total number of adults. We can do this by using the given ratio between adults and children. The ratio of adults to children is 5:6, which means that for every 5 adults, there are 6 children.
Since we know that there are 102 children in the library, we can use this information to calculate the number of adults. The ratio tells us that there are 6 children for every 5 adults. Therefore, we can set up the equation: 6 children = 5 adults. To solve for the number of adults, we can multiply both sides of the equation by 5/6: 6 * 5/6 = 5 adults * 5/6. This simplifies to: 5 = 25/6 adults.
To convert this fraction into a whole number, we can multiply both sides of the equation by 6: 5 * 6 = 25/6 * 6. This gives us: 30 = 25 adults. Now that we know there are 25 adults and 102 children in the library, we can determine the total number of people by adding these two numbers together: 25 adults + 102 children = 127 people. Therefore, there are 127 people in the library altogether.
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Answer:
b = 12
Step-by-step explanation:
The mistake Megan has made is that she has squared the lengths and then added it instead of taking away the squared length's. The method she used was to work out the hypotenuse, so the correct method would be as follows:
a² + b² = c²
→ Substitute in the values
5² + b² = 13²
→ Simplify the equation
25 + b² = 169
→ Minus 25 from both sides to isolate b²
b² = 144
→ Square root both sides to find the value of b
b = 12
Not enough information, please attach a photo next time.
B. y = tan x
C. y = cot x
D. y = csc x
Answer:
B. y = tan x and C. y = cot x
Step-by-step explanation:
Range:
range is defined as the set of values that any given function y=f(x), can take for which the x values are defined. It is the value that y can take for the values of x.
Given:
From the given options
the range of tanx and cotx are all real numbers
as the period of tanx and cotx are π
where as range of secx is all real numbers except π/2 + n*π i.e.
(-∞ , -1] U [1 , + ∞)
And range of cscx is all real numbers except n*π i.e.
(-∞ , -1] U [1 , + ∞)
So from the given option:
option B and C are correct while A and D are not !
The answer is: The correct options are B. Tan(x) and C. Cot(x)
The range is the output of a function when we evaluate the function with inputs (domain), not all functions have a range of all real numbers, however it's more common to find functions without range or domain restrictions.
Both options B. Tan(x) and C. Cot(x) have a range of all real numbers while the functions Sec(x) and Csc (x) have a restricted range.
Sec(x) and Csc(x):
Domain, all real numbers.
Range, from -1 to 1 or [-1,1]
Tan(x) and Cot(x):
Domain, all real numbers except
Range, all real numbers.
Hence, the correct options are B. Tan(x) and C. Cot(x)
Have a nice day!