y(y + 5) = 750
y2 – 5y = 750
750 – y(y – 5) = 0
y(y – 5) + 750 = 0
(y + 25)(y – 30) = 0
Answer:
Option B , C and E are correct
(y+25)(y-30)=0
Step-by-step explanation:
Given : Area of rectangular room is 750 square feet.
Width of the room is 5 feet less than the length of the room.
Let y be the length of the room
then,
As per the given condition
width of the room is: y-5
Area of rectangle is multiply the length by its width.
Area of rectangle =
Substitute the given values in above formula we get;
......[1]
or we can write this as;
750 -y(y-5)=0
[1] ⇒ or
or
(y+25)(y-30)=0
Therefore, the equation which can be used to solve for y are;
, and (y+25)(y-30)=0
Answer:
729
Step-by-step explanation:
C(x) = 6x + 3 (in USD)
Given:
Question:
The equation that represents cost, C(x), ice skating as a function of x, the number of hours of skating.
The Process:
We try solving a word problem about the single variable equation.
Step-1: calculate the cost of skates per hour.
Let the rate of using the skating rink be R per hour. We will seek the value of R.
On that day Gillian rented skating for 3 hours and paid $ 21. The equation that will determine this given by:
Both sides subtracted by 3.
We isolate R on the left side. Both sides are divided by 3.
Hence, the fee of skates per hour is
Step-2: determine the cost equation for ice skating
Let x as the number of hours of skating.
Recall the fee of skates per hour is $6 and the fee to rent is $3 for the day.
Thus, the equation which represents the cost of ice skating as a function of x, the number of hours of skating, will be given by:
(in USD)
Keywords: the ice skating rink, charges an hourly fee, Gillian rented skates, the equation represents the cost, C(x), a function of x, the number of hours of skating, a word problem, the single variable equation
Answer:
-6, 8
Step-by-step explanation:
Let the numbers be represented by y
Square of y = y^2
Double y = 2 × y = 2y
Square of the number is 48 more than double the number is written mathematically as
y^2 = 2y +48
y^2 - 2y - 48 = 0
This is a quadratic equation and can be solved by method of factorisation
y^2 -2y - 48 = 0
y^2 + 6y - 8y - 48 = 0
(y^2 + 6y) - (8y - 48) = 0
y(y + 6) - 8(y + 6) = 0
(y + 6)(y - 8) = 0
y = -6, 8
The numbers are -6, 8
Answer:
8, -6
Step-by-step explanation:
Let the number be $n$, so we have $n^2 =48 + 2n$. Rearranging this equation gives $n^2 -2n-48=0$ and factoring gives $(n-8)(n+6)=0$. So, the numbers that fit the problem are $\boxed{n = -6~\text{and}~n = 8}$.
to EFGH?
I need help
immediately!!!