PHYSICS HIGH SCHOOL

How to do this problem

Answers

Answer 1

Answer:

Answer:

v = 12,4 m/s

Explanation:

frictionless means all gravitational Energie (Eg) will be converted to kinetic Energie (Ek)

Ek = 0.5 * m * v^2

Ez = m * g * h

Ek = Ez

0.5 * m * v^2 = m * g * h

divide left and right of the = sign by m.

(This means that the final velocity is independent of the mass of both children !)

0.5 * v^2 = g * h

v^2 = 2 * g * h

v = +- SQRT (2 * g * h)

with

g = 9.8 m/s^2

h = 7,8 m/s

v = +- SQRT (2 * 9.8 * 7.8)

v = +- SQRT (152.88)

(v = - 12,4 m/s has no meaning in this case)

The velocity 7,8 m below the starting point, will be

v = 12,4 m/s

Answer 2

Answer:

Answer:

the answer is 336.96 mph

Explanation:

hope this helps ^_~

Related Questions

When heating a substance, a phase change will start to occur when the kinetic energy of the particles is _____________ the attractive forces between the particles. Question 8 options: A. great enough to combine B. low enough to combine C. low enough to overcome D. equal to E. great enough to overcome
walking converts what type of energy into mechanical energy? A) chemical B) electromagnetic C)nuclear D)thermal
Why do you think sound travels faster in steel than it does in wood? (Hint: Think about the densities of the two materials, and how the particles might be arranged.)
When an object falls through air, there is a drag with dimensions ml/t2 that depends on the ________. 1) size of the object 2) mass of the object 3) velocity of the object 4) density of the air
_______ are an especially good indicator of climate change because scientists can find clues about ancient organisms and their environments.

BAlpha Centauri has an apparent magnitude of -0.27, whereas the apparent
magnitude of Alpha Crucis is 0.77. Identify which star appears brighter when observed from
Earth. Explain your answer.

Answers

Answer:

Alpha centauri will be brighter than Alpha Crucis .

Explanation:

Apparent magnitude of a star measures how bright a star is .

This scale is reverse logarithmic ie , the brighter the star , the lower is its magnitude . A magnitude equal to 5 scale higher represents less magnitude by a factor of 1/ 100 . In this way a difference of 1 magnitude represents a brightness ratio of 2.512 . Hence a star of brightness magnitude of 7 is less bright by a factor 2.512 than that of a star magnitude of 6 .

Phase changes are not associated with a change in

Answers

Phase changes are not associated with a change in frequency,
wavelength, amplitude, color, volume, mass, national origin,
ethnicity, loudness, weight, opacity, or unit cost.

Two objects are connected by a light string that passes over a frictionless pulley as shown in the figure below. Assume the incline is frictionless and take m1 = 2.00 kg, m2 = 7.35 kg, and θ = 50.0°.1) Find the magnitude of the accelerations of the objects. (m/s^2)
2)Find the tension in the string. (N)
3)Find the speed of each object 2.50 s after being released from rest. (m/s)

Answers

Answer:

Part a)

$a = 3.81 m/s^2$

Part b)

$T = 27.2 N$

Part c)

$v_f = 9.53 m/s$

Explanation:

For m2 mass along the inclined plane we can write

$m_2g sin\theta - T = m_2 a$

for m1 mass we can write equation in vertical direction

$T - m_1 g = m_1 a$

so we will have

$m_2g sin\theta - m_1g = (m_1 + m_2) a$

so we have

$a = ((m_2 sin\theta - m_1)g)/(m_1 + m_2)$

now plug in all data in it

$a = ((7.35 sin50 - 2)9.81)/(7.35 + 2)$

$a = 3.81 m/s^2$

Part b)

from above equation

$T = m_1g + m_1 a$

$T = 2(9.81 + 3.81)$

$T = 27.2 N$

Part c)

Speed of the object after t = 2.50 s

$v_f = v_i + at$

$v_f = 0 + 3.81(2.50)$

$v_f = 9.53 m/s$

assume m1 moving down, so m2 is moving up and accelleration direction of each box is the same as its movement.

check forces act on m1
1. tension of the rope T up
2. m1g down
3. moving down with a
f = ma --> m1g - T = m1a ...(1)
or. T = m1g - m1a ... (1.1)

check forces act on m2
1. tension of the rope T up alone the incline. it must be equal to previous one because it is the same segment of the rope.
2. m2gsine(θ) down along the incline
3. moving up with a
f = ma --> T - m2gsine(θ) = m2a ...(2)

replace T from (1.1) to (2)
(m1g - m1a) - m2gsin(θ) = m2a
m1g - m2gsin(θ) = m2a + m1a
a = g(m1 - m2sin(θ))/(m1 + m2)

plug in value you will get the answer. if a is negative, it means direction on our assumption is not correct. it's the opposite (direction).

after get a, you will get T
and velocity use v = u + at

... i cannot post pict. draw the diagram will make you understand this better.

a 5kg mass resting on a smooth horizontal, frictionless table is connected to a cable which passes over a pulley and then is fastened to a hanging 10kg mass. find the acceleration of the two objects and the tension of the string.

Answers

T= 5a

-T +10g = 10a

-15a =10g

a=-10g/15

a= -1/2 g
Negative a means block is accelerating downwards.

What instrument would scientist use to take measurements in the upper troposphere A. x-ray monitor

B. ice core bore

C. weather balloon

D. underwater sonar

Answers

Scientists use the instrument weather balloon to take measurements in the upper troposphere. Answer: C.
The weather balloon uses small device called radiosonde and measures weather parameters like atmospheric pressure, temperature, humidity and wind speed.
These instruments operate in the troposphere.

Scientist use a weather balloon to measurements in the upper troposphere.

What is the namefor the ratio of the
voltage applied to
a circuit and the
current in a circuit?

Answers

Answer:

The relationship between voltage and current is called resistance. The relationship between all 3 is called Ohm's Law.

General Formulas and Concepts:
Circuits

Ohm's Law: V = IR

V is voltage/EMF
I is current
R is resistance

Explanation:

Ohm's Law is the fundamental basic for an ohmic surface. All circuits follow Ohm's Law if it is ohmic and assuming all other things constant. It tells the importance of the relationship between voltage, current, and resistance in a given current of a battery, wire, and resistor.

It is wise that you memorize this and understand the relationship between all 3.

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Learn more about EMAG: brainly.com/question/27293828

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Topic: AP Physics C - Electricity and Magnetism

Unit: Circuits

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