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Melinda earns 5 minutes to play video games for every hour she spends on homework.If Melinda spends 3 hours on homework, how many minutes will she earn to play video games?

Answers

Answer 1

Answer:

Answer:

She gets 15 minutes to play video games.

Step by step:

For every 1 hour = 5 minutes, so 1x3 = 3 hours, 5x3 = 15 minutes.

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Find an equation of the plane. the plane through the point (3, 0, 7) and perpendicular to the line x = 5t, y = 2 − t, z = 8 + 4t

Who can possibly beat me?

A. Kakarot
B. Gohan
C. Broly
D. Frieza

Answers

Answer:

Step-by-step explanation:

Answer c

Explanation

The computer that controls a bank's automatic teller machine crashes a mean of 0.5 times per day. What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

Answers

Answer:

0.3216 = 32.16% probability that, in any seven-day week, the computer will crash less than 3 times

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval

Mean of 0.5

7-day week, so $\mu = 7*0.5 = 3.5$

What is the probability that, in any seven-day week, the computer will crash less than 3 times?

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

$P(X = 0) = (e^(-3.5)*(3.5)^(0))/((0)!) = 0.0302$

$P(X = 1) = (e^(-3.5)*(3.5)^(1))/((1)!) = 0.1057$

$P(X = 2) = (e^(-3.5)*(3.5)^(2))/((2)!) = 0.1850$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0302 + 0.1057 + 0.1857 = 0.3216$

0.3216 = 32.16% probability that, in any seven-day week, the computer will crash less than 3 times

Final answer:

To find the probability that the computer will crash less than 3 times in a seven-day week, we can use the binomial probability formula.

Explanation:

To find the probability that the computer will crash less than 3 times in a seven-day week, we can use the binomial probability formula. The formula for binomial probability is:

$P(X = k) = C(n, k) * p^k * (1-p)^{(n-k)$

Where:

P(X = k) is the probability of exactly k successes
C(n, k) is the combination function for choosing k items from a set of n
p is the probability of success for each individual trial
n is the number of trials

In this case, the mean number of crashes per day is 0.5, which means the probability of a crash in a single day is 0.5. Since we're interested in the probability of less than 3 crashes in a seven-day week, we can calculate P(X < 3) using the binomial probability formula with n = 7, p = 0.5, and k = 0, 1, 2:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

Using the binomial probability formula, we can calculate:

$P(X = 0) = C(7, 0) * 0.5^0 * (1-0.5)^(^7^-^0)\nP(X = 1) = C(7, 1) * 0.5^1 * (1-0.5)^(^7^-^1)\nP(X = 2) = C(7, 2) * 0.5^2 * (1-0.5)^(^7^-^2)$

Adding these probabilities together will give us the probability of less than 3 crashes in a seven-day week.

Rounding the final probability to four decimal places, we get the probability that the computer will crash less than 3 times in a seven-day week.

Learn more about Binomial probability here:

brainly.com/question/39666605

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Ac and bd are perpendicular bisectors of each other. adc. Find eab

Answers

Let ∠ ADC = 2β

Ac and BD are perpendicular bisectors of each other ⇒⇒ (Given information)

∴ BD bisects the angle ADC
∴ ∠ADE = 0.5 ∠ADC = β

And in ΔADE:
∵∠DEA = 90° ⇒⇒⇒ from the given information
∴∠DAE = 90° - β

And AC bisects ∠DAB ⇒⇒⇒ from the given information
∴∠EAB = ∠DAE = 90° - β

<EAB = 180 - 90 - (0.5*<ADC)

You have a triangle that has side lengths of 6,9,and 12. Give the side lengths of a similar triangle that is smaller than the given triangle.

Answers

Those lengths have a common factor of 3. Removing that factor gives you the smaller similar triangle with sides 2, 3, and 4.

Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.Work out the total amount of money in the account at the end of 3 years.
Give your answer to the nearest rupee.

Answers

Answer:

There will be 20 914 rupees in the amount at the end of 3 years.

Step-by-step explanation:

The amount of rupes after t years in compound interest is given by:

$A(t) = A(0)(1+r)^(t)$

In which A(0) is the initial amount and r is the interest rate, as a decimal.

Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.

This means that $A(0) = 20000, r = 0.015$ . So

$A(t) = A(0)(1+r)^(t)$

$A(t) = 20000(1+0.015)^(t)$

$A(t) = 20000(1.015)^(t)$

Work out the total amount of money in the account at the end of 3 years.

This is A(3). So

$A(3) = 20000(1.015)^(3) = 20913.6$

Rounding to the nearest rupee.

There will be 20 914 rupees in the amount at the end of 3 years.

Final answer:

Hiran invested 20 000 rupees at 1.5% compound interest for 3 years. By applying the formula for compound interest, the total amount in the account at the end of 3 years would be approximately 20747 rupees.

Explanation:

The subject of this question is compound interest. The formula for calculating compound interest is A = P(1+ r/n)^(nt), where 'A' is the amount of money accumulated after n years, including interest. 'P' is the principal amount (the initial amount of money), 'r' is the annual interest rate (in decimal), 'n' is the number of times that interest is compounded per year, and 't' is the time the money is invested for in years.

In the given problem, Hiran has invested a principal amount of 20 000 rupees for 3 years at an annual interest rate of 1.5%. So, here P=20 000, r=1.5/100=0.015 (since 1.5% = 1.5/100 = 0.015), n=1 (since it is annually), and t=3.

By substituting these values into the formula, we get A = 20 000(1+ 0.015/1)^(1*3) which results in approximately 20747 rupees. This denotes the total amount in the account at the end of 3 years.