A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded. The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B: 4.90 hrs < μ1 - μ2 < 17.50 hrs
What does the confidence interval suggest about the population means?
A. The confidence interval includes 0 which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
C. The confidence interval includes only positive values which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
Answers
This question is not complete, I got the complete one from google as below:
A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded.
The summary statistics are as follows.
Type A Type B
x1 = 76.3 hrs x2 = 65.1 hrs
s1 = 4.5 hrs s2 = 5.1 hrs
n1 = 11 n2 = 9
The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B:
4.90 hrs < μ1 - μ2 < 17.50 hrs
What does the confidence interval suggest about the population means?
A. The confidence interval includes 0 which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
C. The confidence interval includes only positive values which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
Answer:
Option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
Step-by-step explanation:
The 98% confidence interval for the difference in mean drying times of the two types of paints is (4.90, 17.50). This implies that Type A takes between 4.90 and 17.50 hours more to dry than type B paint.
Thus, option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
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Apply the Distributive Property 5(x + 3)
In need of help asap! ? With steps
. Solve for x.10xy=W
Please help me now.....
Answers
Add 5 to both sides
-4= 2x
Divide by 2
-2=x or x=-2
alligators
Crocodi
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
Alligator
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
Length
What are the differences between the centers and spreads of these
distributions?
Select two choices: one for the centers and one for the spreads
D A Centers: The crocodiles have a lower median length than the
alligators
B. Centers: The crocodiles have a greater median length than the
alligators
c. Spreads: The lengths of the alligators are more spread out
D. Spreads. The lengths of the crocodiles are more spread out
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Answers
Answer:
(B) Centers: The crocodiles have a greater median length than the alligators
(C) Spreads: The lengths of the alligators are more spread out
Step-by-step explanation:
The question is incomplete without the diagram. Find attached the diagram used in solving the question
Centers: this is the median of the distribution
Spread: this is the variation of the data distribution. The range can be used to find the spread. If the range is large, the spread is larger and If the range is small, the spread is smaller.
Range = highest value - lowest value
From the diagram:
Median of crocodile = 17
Median of the alligator = 9
Therefore, for Centers: The crocodiles have a greater median length than the alligators (option B)
Spread for crocodile data = from 15 to 19
Range = 19-15 = 4
Spread for alligator data = from 7 to 15
Range = 15-7 = 8
For Spreads: The lengths of the alligators are more spread out.
Answer: b and c
Step-by-step explanation:
Methylparaben 50 mg
Propylparaben 20 mg
NaCl 800 mg
Purifed water qs ad 100 mL
Answers
Answer:
There are 100 milligrams of metoclopramide HCl in each milliliter of the prescription
Step-by-step explanation:
When the prescription says Purified water qs ad 100 mL means that if we were to make this, we should add the quantities given and then, fill it up with water until we have 100 mL of solution, being the key words qs ad, meaning sufficient quantity to get the amount of mixture given.
Then, knowing there is 10 grams of metoclopramide HCl per 100 mL of prescription, that means there is (1 gram = 1000 milligrams) 10000 milligrams of metoclopramide HCl per 100 mL of prescription. That is a concentration given in a mass/volume way.
Knowing the concentration, we can calculate it per mL instead of per 100 mL
Answers
Answer:
6/(-2) = -3
Step-by-step explanation:
rule - when you divide positive number by a negative number then it is negatie so with the same rule applied it is
6/-2
-3
6 + (-2) means we start at 0 and go up 6 units to arrive at 6 on the number line. In terms of a building, you can think of starting on the ground floor and then going up 6 floors. Then adding on the -2 means we go down 2 floors to arrive at 6 + (-2) = 6-2 = 4
Answer: Choice B) go up 6, then down 2
(x^2 - 4) (x - 1)
Answers
(x2 + x + 2) • (x - 2)
—————————
x - 1
x-1 is the answer!!!!! :)
Answers
Answer:
8
Step-by-step explanation:
uh idrk all ik is that 16,000 punds = 8 tons
16,000 pounds equals 8 tons