Answer:
no
Step-by-step explanation:
A. 94 cm2
C. 60 cm
B. 70 cm2
D. 47 cm
Answer:
94 cm2
Step-by-step explanation:
Base x Width x height
4 x 5 x 3
Answer:
A: 94 cm2
Step-by-step explanation:
the surface area is 94 cm2
Find the number of sides of this polygon.
Answer:
45 sides
Step-by-step explanation:
If each of the interior angles is 172 degrees, then each of the exterior angles is 8 degrees. Since the sum of the exterior angles of any polygon is 360 degrees, there are 360 / 8 = 45 exterior angles and 45 sides.
645 divided by 100
645 divided by 50
48.6 divided by 30
48.6 divided by x
Answer:
645/100 = 129/20 or 6.45
645/50 = 129/10 or 12.9
48.6/30 = 1.62
48 divided by x = 48.6/x
Step-by-step explanation:
645/100
Factor the number:
= 5*129/100
Factor the number:
= 5*129/5*20
Cancel the common factor:
= 129/20
645/50
Factor the number:
5*129/50
Factor the number:
5*129 / 5*10
Cancel the common factor:
= 129/10
48.6/30
Write the problem in long division format
Multiply the quotient digit (1) by the divisor (30)
Subtract 30 from 48
Add a decimal and bring down the next number
Divide 186 by 30 to get 6
Continue...A few steps later...
Subtract 60 from 60
Solution is 1.62
48.6/x
Re-write division as a fraction:
48.6/x
Answer:
There are 14 horses and 21 chickens.
Step-by-step explanation:
First, you have to make expression for horse and chicken. So we can let x be the number of horses and y will be the number of chickens. Next, given that the total number of feet for both animals is 98 so you have to make simultaneous equation :
(horse has 4 feet and chicken has 2 feet)
There are a total of 35 heads so the other equation will be :
Lastly, you have to solve it :
The curve representing the relationship includes the point
The growth factor is
An earthquake with an energy level of has a magnitude of
The equation 'M = 0.6666 log x - 3.2' describes the relationship between the energy produced by an earthquake (x) and its resulting magnitude (M). The 0.6666 in the formula is the growth factor. To get a magnitude for a specific energy level, we plug the energy value into the formula, and solve.
The equation given represents the relationship between the magnitude of an earthquake (M) and the energy it produces (x), with M being the earthquake's magnitude and x being the energy produced by the earthquake. This equation is a logarithmic model with a base of 10 (without the base explicitly stated, we assume it to be 10).
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Answer:
Step-by-step explanation:
(a) For n = 6, CL = 90%,
The degrees of freedom: 5, Critical t-value: 2.571
(b) For n = 21, CL = 98%,
The degrees of freedom: 20, Critical t-value: 2.845
(c) For n = 29, CL = 95%,
The degrees of freedom: 28, Critical t-value: 2.048
(d) For n = 12, CL = 99%,
The degrees of freedom: 11, Critical t-value: 3.106
Use the concept of critical t- value defined as:
A critical value is a number that is used in hypothesis testing to compare to a test statistic and evaluate whether or not the null hypothesis should be rejected. The null hypothesis cannot be rejected if the test statistic's value is less extreme than the crucial value.
(a) Given that,
n = 6 and a confidence level of 90%,
The degrees of freedom are,
n-1 = 6-1
The degrees of freedom = 5.
To find the critical t-value,
Look it up in the t-distribution table using a confidence level of 90% and a degree of freedom of 5.
From the table,
The critical t-value is approximately 2.571.
(b) Given that,
n = 21 and a confidence level of 98%,
The degrees of freedom are,
n-1 = 21-1
The degrees of freedom = 20.
By referring to the t-distribution table with a confidence level of 98% and degrees of freedom of 20,
The critical t-value is approximately 2.845.
(c) Given that,
n = 29 and a confidence level of 95%,
The degrees of freedom are,
n-1 = 29-1
The degrees of freedom = 28
Using the t-distribution table with a confidence level of 95% and degrees of freedom of 28,
The critical t-value is approximately 2.048.
(d) Given that,
n = 12 and a confidence level of 99%,
The degrees of freedom are,
n-1 = 12-1
The degrees of freedom = 11
By consulting the t-distribution table with a confidence level of 99% and degrees of freedom of 11,
The critical t-value is approximately 3.106.
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To find the degrees of freedom and critical t-value for each given sample size and confidence level, we can use the t-distribution and a t-table. The degrees of freedom (df) for each sample is equal to the sample size minus 1. The critical t-value can be found using the t-table with the corresponding degrees of freedom and the confidence level.
To find the degrees of freedom and critical t-value for each given sample size and confidence level, we can use the t-distribution and a t-table. The degrees of freedom (df) for each sample is equal to the sample size minus 1. For example, for (a) n = 6, df = 6 - 1 = 5. The critical t-value can be found using the t-table with the corresponding degrees of freedom and the confidence level.
For (a) n = 6, CL = 90%, the critical t-value is approximately 1.943.
For (b) n = 21, CL = 98%, the critical t-value is approximately 2.861.
For (c) n = 29, CL = 95%, the critical t-value is approximately 2.045.
For (d) n = 12, CL = 99%, the critical t-value is approximately 3.106.
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