MATHEMATICS HIGH SCHOOL

What is the check for this equation?
4(1 - x) + 3x = -2(x + 1)

Answers

Answer 1
Answer: x = -6 hope that helps :)

Related Questions

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A certain bank offers a car loan with a fixed annual interest rate. Justine applied for the loan and used the entire amount to buy a car worth $43,000. He had to pay the bank for five years for a total amount of $51,600. How much would be the yearly interest if Justine borrowed $50,000 instead? *0 points
10.) Sally cooks 6 pies and each pie is cut into 8 pieces. If she sells 36 pieces, what percentage did she sell
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How does the concept of trust relate to debt?

Answers

Answer:

A trust can protect your assets for the next generation. However, if you have debt, the trust will not necessarily protect assets from creditors. If you or your beneficiaries file for bankruptcy, for example, the trust could be seized for repayment of debts.

Janine wishes to conduct a poll to predict how many students will vote for her for class president. Which polling methods are likely to be biased? Choose all answers that are correct. A. Five people in each of Janine’s classes are selected and asked for whom they intend to vote. B. From a list of all students in Janine’s grade, 25 students are selected at random and asked for whom they intend to vote. C. Every 10th student from a list of all students in Janine’s grade is selected and asked for whom the student intends to vote. D. Janine chooses 5 of her friends and asks each to select another 5 students. These 25 students are asked for whom they intend to vote.

Answers

D since she is asking her friends who are just going to ask their friends
A. since only 5 are asked

What are the zeros of the function F of X equals X squared -13 X -30

Answers

Hello,

x²-13x-30=0
==>x²-15x+2x-30=0
==>x(x-15)+2(x-15)=0
==>(x-15)(x+2)=0
==>x=15 or x=-2

Determine the general solution of:

sin 3x - sin x = cos2x

Answers

sin³ x-sin x=cos ² x

we know that:
sin²x + cos²x=1  ⇒cos²x=1-sin²x
Therefore:

sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0

sin³x=z

z³+z²-z-1=0

we divide by Ruffini method:
              1     1     -1     -1
        1           1      2      1                z=1
-------------------------------------
              1     2      1      0
       -1         -1      -1                       z=-1
--------------------------------------
              1     1       0                       z=-1

Therefore; the solutions are z=-1 and z=1

The solutions are:
if z=-1, then
sin x=-1   ⇒x= arcsin -1=π+2kπ    (180º+360ºK)   K∈Z


if z=1, then
sin x=1   ⇒ x=arcsin 1=π/2 + 2kπ   (90º+360ºK)   k∈Z

π/2 + 2kπ    U   π+2Kπ=π/2+kπ     k∈Z    ≈(90º+180ºK)

Answer: π/2 + Kπ    or     90º+180ºK          K∈Z
Z=...-3,-2,-1,0,1,2,3,4....

Solve each equation 1) log5-log2x=1 2) 2log(x+1)=5

Answers

1)\nlog5-log2x=1;\ D:x > 0\n\nlog(5:2x)=log10\n\nlog(5)/(2x)=log10\iff(5)/(2x)=10\n\n20x=5\ \ \ /:20\n\nx=(1)/(4)\in D


2)\n2log(x+1)=5;\ D:x+1 > 0\to x > -1\n\nlog(x+1)^2=log10^5\iff(x+1)^2=10^5\n\nx+1=-√(10^5)\ \vee\ x+1=√(10^5)\n\nx+1=-√(10^4\cdot10)\ \vee\ x+1=√(10^4\cdot10)\n\nx=-100√(10)-1\notin D\ \vee\ x=100√(10)-1\in D

If tanx = 0.75, find the value ofi. cos2x + sin2x
2tanx
ii.
for 0° < x < 90°
C0Sx-sinx
-

Answers

Answer:

i. 31/25

ii. 1/5

Step-by-step explanation:

you know that tanx = 3/4, so you can also find that sinx = 3/5 and cosx = 4/5. Then you can use the double angle identities to find cos2x and sin2x: cos^2(x) - sin^2(x) + 2sinxcosx and substitute the givens to get 31/25. Then, cosx - sinx is obviously 1/5.

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