Answer:
True
Step-by-step explanation:
As there are infinite numbers, the list of multiples are also infinite.
Multiples of 6 : 6, 12 , 18 , 24 ..............
Answer:
True; yes.
Step-by-step explanation:
Think about it, what does etc, etc mean? It means repetitive-a pattern, in a sort of way. So here are some multiples of 6:
6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,144,150,156,162,168,174,180,186,192,198,204,210,216,222,228,234,240,246,252,258,264,270,276,282,288,294, etc.
As you can see, all I'm doing is adding 6 to every step I go. So when you say there is an infinite number, then these multiples are going to be infinite.
x^2 + 2x = 42
x^2 + x + 42 = 0
x^2 + 2x + 42 = 0
Answer:
The correct answer is x^2 + x = 42.
Step-by-step explanation:
First, we need to declare the unknown, as usual we will use x for the number. Then, the square of the number will be x^2. Following the order of the statement we have that x + x^2 =42. Here we have ‘‘translated’’ the term the sum in the mathematical operation of addition. Moreover, we convert the fact that the sum of a number and its square is 42 in a equality. This is the explanation of the equation x + x^2 =42.
Finally, using that the addition is commutative we have that x^2+x=42.
Function A Least Rate, Function B, Function C Greatest Rate.
To determine the rate of change of each linear function, we can look at their slopes. The slope of Function A can be found by taking the difference between the y-coordinates of any two points on the line and dividing by the difference between the corresponding x-coordinates. For example, using the points (0, 1) and (2, 4), we can find the slope of Function A as (4-1)/(2-0) = 3/2.
The slope of Function B can be found by using the given intercepts, which means the slope of Function B is -2/3 (as the line passes through the points (0,2) and (3,0)).
The slope of Function C can be found by rearranging the equation y = -3x + 4 into the slope-intercept form y = mx + b, where m is the slope and b is the y-intercept. Therefore, the slope of Function C is -3.
Hence, we can see that the slope of Function A is 3/2, which is the least among the given functions. The slope of Function B is -2/3, which is greater than the slope of Function A. The slope of Function C is -3, which is the greatest among the given functions. Therefore, the order of the linear functions based on the rate of change, from least to greatest, would be Function A, Function B, Function C.
Learn more about Least Rate here
#SPJ11
Answer:
The required expression is
Step-by-step explanation:
The difference of squares formula is given by
We have been given that one factor is 2x+5. Hence, a = 2x, b = 5
It means that other factor must be (a-b) = (2x-5)
Hence, in order to find the expression, we can multiply the factors.
Using the difference of squares formula
Therefore, the required expression is
Answer:
Let's say we have an expression x * y + z * w, where x, y, z and w are numbers.
We can use the commutative property to change the order of the summands:
x * y + z * w = y * x + w * z = (y + z) * x + w
Since we have a sum of two products, we can use the associative property to combine them:
(y + w) * (x + 15) = 160
By dividing both sides of the equation by 2, we get:
(y + w) / 2 * (x + 15) / 2 = 80
We can then simplify this expression using the distributive property:
(y / 2) + (w / 2) * (x / 2) + (15 / 2)
Since the numbers are all positive, we can cancel out the halves on the left, and combine the remaining terms:
y / 2 + (w / 2) * x + 15 / 2 = 80
Finally, we can simplify this expression by dividing both sides of the equation by the constant fraction:
y / 2 + (w / 2) * x + 15 / 2 = 80
(y / 2) + (w / 2) * (x / 2) + (15 / 2) = 80
Simplifying this expression, we get y / 2 + (w / 2) * x / 2 + 15 / 2 = 40.
By simplifying the last term further, we get:
y / 2 + (w / 2) * x / 2 + 7.5 = 40
Therefore, the equation that simplifies to 160 is this one:
y / 2 + (w / 2) * x / 2 + 7.5
I hope this helps!
(x + 1)(2x^2 + 3x - 1) : Can be solved in multiple ways but easiest for me :P
x (2x^2 + 3x - 1) + 1(2x^2 + 3x - 1)
(2x^3 + 3x^2 - x) + (2x^2 + 3x - 1)
2x^3 + 5x^2 + 2x - 1