the answer to your question is x=0
X=0
−32−8x=−7x+8(8x−4)
−8x−32=−7x+8(8x−4)
−8x−32=−7x+64x−32
−8x−32=57−32
−8−32+32=57−32+32
−8=57
6x = 66
8x = 56
9x = 54
Answer:
D 9x=54
Step-by-step explanation:
just look at it as 9times6=54 .
Since the origin is the center of dilation then the factor of dilation is 2 so just multiply the coordinate of every vertex by 2. So, the vertices will become A'(-2,-2), B'(0, 2), C'(4, 4) ad D'(4,-2). Therefore, letter B is the answer.
(b). Find the volume of the solid generated when R is revolved about the line y=-2.
Volume of the solid generated when R is revolved about the x-axis is 10π and the volume of the solid generated when R is revolved about the line y = -2 is 40π/3.
Graph is a mathematical representation of a network and it describes the relationship between lines and points.
The volume of the solid generated when R is revolved about the x-axis,
where a and b are the x-coordinates of the points of intersection of the curve y = √(x-2) and the line y = 2.
Solving y = √(x-2) and y = 2 for x, we get:
x = 6 and x = 2
Limits of integration are a = 2 and b = 6. Substituting y = √(x-2) into the formula for the volume, we get:
V =
V= π [(6²/2 - 2(6)) - (2²/2 - 2(2))]
=10π
Volume of the solid generated when R is revolved about the x-axis is 10π.
b. The volume of the solid generated when R is revolved about the line y = -2
Substituting y = √(x-2) into the formula for the volume, we get:
We can simplify this by using the identity:
V =40π/3
Therefore, the volume of the solid generated when R is revolved about the line y = -2 is 40π/3.
Hence, Volume of the solid generated when R is revolved about the x-axis is 10π and the volume of the solid generated when R is revolved about the line y = -2 is 40π/3.
To learn more on Graph click:
#SPJ6