MATHEMATICS MIDDLE SCHOOL

I need help with this math equation. It's about quadratic equation.Identify a, b, and c in the following quadratic equation 3x^2−7x=12.
A=
B=
C=

Answers

Answer 1

Answer:

Answer:

A = 3

B = -7

C = -12

Step-by-step explanation:

3x^2−7x=12.

The standard form for a quadratic equation is

Ax^2 +Bx +C =0

Subtract 12 from each side

3x^2−7x-12=12-12

3x^2−7x-12=0

A = 3

B = -7

C = -12

Answer 2

Answer:

a = 3

b = -7

c = -12

Step-by-step explanation:

General form of a quadratic:

ax² + bx + c

Given:

3x² − 7x = 12

3x² - 7x - 12 = 0

Comparing the two:

a = 3

b = -7

c = -12

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A right triangle has the leg lengths of 3X and 40 and a hypotenuse of length 5X. How long are the sides?
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A piece of wood is to be cut so that it is square and has an area of 45 square inches. How long should the sides be, rounded to the nearest tenth of an inch?a.
6.7 inches
c.
8.6 inches
b.
22.5 inches
d.
11.3 inches

Answers

A 6.7 u take the square root of 45

How to find the volume of the cone

Answers

Answer:

The closest measurement to the volume of hat is 84.82 in.³.

Step-by-step explanation:

Given:

The dimensions of hat are height(h) 9 inches and diameter(d) 6 inches.

Now, to find the volume of cone:

Putting the formula $(1)/(3)\pi r^(2)h$ .

Radius(r) is not given, finding the radius:

Radius(r)=half of the diameter(d)

$r=(d)/(2)$

$r=(6)/(2)$

$r=3$ .

Then, $(1)/(3)\pi r^(2)h$

= $(1)/(3)*\pi *3^(2)*9$

= $(1)/(3)*3.14*9*9$ ( $\pi =3.14$ )

= $(1)/(3) *254.34$

= $(254.34)/(3)$

= $84.78$ in.³

So, the volume is 84.78 in.³ .

Therefore, the closest measurement to the volume of hat is 84.82 in.³.

At 6 PM the temperature was -2 Fahrenheit by Midnight The temperature had dropped 7° what was the temperature at midnight

Answers

-9 degrees Fahrenheit

Answer:

Probbly -9 degrees Fahrenheit

Step-by-step explanation:

Point D is on segment SF. If SF is 72 cm and DF is 62, what is the measurement of segment SD ?

Answers

SD=SF-DF
SD=72-62=10cm

If D is on segment SF then |SD| + |DF| = |SF|.

We have:

|SF| = 72 cm
|DF| = 62 cm

substitute:

|SD| + 62 cm = 72 cm |-62 cm

|SD| = 10 cm

List the partial products for this problem 252 x 605

Answers

one way to do partial products is 252 times 600+252 times 5
simplified further into

200 times 600+50 times 600 + 2 times 600+200 times 5 +50 times 5 + 2 times 5

8×43= use expanded form